Answer:
12J
Explanation:
Given parameters:
Mass = 1.5kg
Impulse = 6kgm/s
let us start first by find the velocity with which this body moves;
Impulse = mass x velocity
Velocity = Impulse / mass = 6/ 1.5 = 4m/s
Initial velocity = 0m/s
Unknown:
Resulting kinetic energy = ?
Solution:
To solve this problem use the formula below:
K.E = m (v - u)²
m is the mass
v is the final velocity
u is the initial velocity
So;
K.E = x 1.5 x (4 - 0)²
K.E = 1.5 x 8 = 12J
Answer:
<em>529.2N </em>
Explanation:
Given parameters:
Mass of the object = 54kg
Unknown:
Gravitational force acting on the mass = ?
Solution:
To solve this problem, the gravitational force acting on this body is tantamount to the weight of the object.
So;
Weight = mg
m is the mass
g is the acceleration due to gravity
Now;
Weight = 54 x 9.8 = <em>529.2N </em>
The gravitational force acting on the object is <em>529.2N </em>
Answer: I only have the answer for A, but still, the answer is 20.07.
- Explanation: Because the number ends in a 15, round to the nearest tenth which is 20. So now the number is 5420.
- To get the Watts (W) you have to take 5420 and divide it by the time in seconds. 4.5 minutes in seconds is 270, so 5420 divided by 270 equals 20.07.
- So 20.07 is the answer.
Answer:
false a curciut is just a loop of electricity goes in and negative comes out when using a battery the negative goes in and the goes out making a battery have two sides to a uircute.
hope this helps!
Explanation:
Answer:
7.72 Liters
Explanation:
normal body temperature = T_body =37° C
temperature of ice water = T_ice =0°c
specfic heat of water = c_{water} =4186J/kg.°C
if the person drink 1 liter of cold water mass of water is = m = 1.0kg
heat lost by body is Qwater =mc_{water} ΔT
= mc{water} ( T_ice - T_body)
= 1.0×4186× (0 -37)
= -154.882 ×10^3 J
here negative sign indicates the energy lost by body in metabolic process energy expended due to brisk - hour long walk is Q_{walk} = 286 kilocalories
= 286×4186J
so number of liters of ice water have to drink is
n×Q_{water} =Q_{walk} n= Q_{walk}/ Q_{water}
= 286×4186J/154.882×10^3 J
= 7.72 Liters