T<u>he statement which fairly compares segment 2 and segment 3 </u>is These represent equal periods of time, but the force during segment 2 is different than the force during segment 3.
Since segment 2 starts at t = 60 s and ends at t = 150 s, the time interval is Δt = 150 - 60 = 90 s.
Also, segment 3 starts at t = 150 s and ends at t = 240 s, the time interval is Δt = 240 - 150 = 90 s.
So, their time periods are the equal.
We notice that segment 2 is less steep than segment 3 this implies that the acceleration in each segment is different, since the acceleration is the slope of the graph.
Since force is determined by acceleration, this implies that the force on segment 2 is different form the force acting in segment 3.
So, we have equal time periods but different forces.
So, <u>the statement which fairly compares segment 2 and segment 3 </u>is These represent equal periods of time, but the force during segment 2 is different than the force during segment 3.
Learn more about velocity-time graph here:
brainly.com/question/24788847
Answer:
Check the explanation
Explanation:
The beat frequency is
df = f2 - f1
the wavelength is
lamda1 = (v/f1)
and lamda2 = (v/f2)
where v = 340 m/s,f1 = 25.0 kHz and f2 = 20.0 kHz
Answer:position relative to the starting point
Explanation:
Objects have the same velocity only if they are moving at the same speed and in the same direction. Objects moving at different speeds, in different directions, or both have different velocities.
