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Solnce55 [7]
3 years ago
6

How much Tension force is required to pull a 1500 kg car (it is being towed) forward with an acceleration of 3 m/s^2 if the fric

tion force on the towed car's tires is pulling backward with a force of 2500 N?
Physics
1 answer:
stiv31 [10]3 years ago
4 0

If the pull is done horizontally, then the net force on the car is

∑ <em>F</em> = <em>T</em> - <em>f</em> = (1500 kg) (3 m/s²)

where <em>T</em> is the magnitude of the tension in the towing cable, and <em>f</em> is the friction which points in the opposite direction. Then

<em>T</em> = <em>f</em> + (1500 kg) (3 m/s²)

<em>T</em> = 2500 N + 4500 N

<em>T</em> = 7000 N

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