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Thepotemich [5.8K]
3 years ago
13

Bradley is returning home from a place that is 2 kilometers away. The function y = 2,000 − 90x represents Bradley's distance fro

m home in meters, y, in relation to the number of minutes he walks, x. Which statements about this function are true?
Mathematics
1 answer:
aleksandrvk [35]3 years ago
5 0
These are the statements that accompany this question:

<span>A.The function is a linear function.

B.The function is a nonlinear function.

C.The function does not change at a constant rate.

D.The function is an increasing function.

E.The function changes at a constant rate.

An this is the assesment of each of statement:

</span>
<span>A.The function is a linear function.

TRUE: a linear function can take the forms  Ax + By - C = 0, or y = mb + b

You can verify that y = 2000 - 90 x is of this type.

B.The function is a nonlinear function.

FALSE: we showed the opposite in A)

C.The function does not change at a constant rate.

FALSE: the rate of change of a linear function is constant and it is known as the slope.

D.The function is an increasing function.

FALSE: the value of y decreases as x increases, given that the slope is negative ( -90).

E.The function changes at a constant rate.

TRUE: the constant rate is the slope, i.e. - 90.
</span>
You might be interested in
Using the formula in model 1, choose the correct answers for the total amount and amount of interest earned in the following com
DIA [1.3K]

The total amount is $ 1015.82 and interest amount is $ 165.82

<em><u>Solution:</u></em>

<em><u>The formula for amount when interest is compounded annually is:</u></em>

\mathrm{A}=P\left(1+r}\right)^{n}

Where,

"A" is the total amount

"P" is the principal

"r" is the rate of interest in decimal form

"n" is the number of years

<em><u>From given, $850 at 2% for 9 years, compounded annually</u></em>

P = 850

t = 9 years

r = 2 \% = \frac{2}{100} = 0.02

<em><u>Substituting the given values we get,</u></em>

A = 850(1+0.02)^9\\\\A = 850 \times 1.02^9\\\\A = 850 \times 1.1950\\\\A = 1015.82

Thus total amount is $ 1015.82

Interest amount = Total amount - principal

Interest amount = 1015.82 - 850

Interest amount = 165.82

Thus total amount earned is $ 1015.82 and interest amount is $ 165.82

7 0
3 years ago
Will mark brainliest for the correct answer!
romanna [79]

Part (a)

Focus on triangle PSQ. We have

angle P = 52

side PQ = 6.8

side SQ = 5.4

Use of the law of sines to determine angle S

sin(S)/PQ = sin(P)/SQ

sin(S)/(6.8) = sin(52)/(5.4)

sin(S) = 6.8*sin(52)/(5.4)

sin(S) = 0.99230983787513

S = arcsin(0.99230983787513)

S = 82.889762826274

Which is approximate

------------

Use this to find angle Q. Again we're only focusing on triangle PSQ.

P+S+Q = 180

Q = 180-P-S

Q = 180-52-82.889762826274

Q = 45.110237173726

Which is also approximate.

A more specific name for this angle is angle PQS, which will be useful later in part (b).

------------

Now find the area of triangle PSQ

area of triangle = 0.5*(side1)*(side2)*sin(included angle)

area of triangle PSQ = 0.5*(PQ)*(SQ)*sin(angle Q)

area of triangle PSQ = 0.5*(6.8)*(5.4)*sin(45.110237173726)

area of triangle PSQ = 13.0074347717966

------------

Next we'll use the fact that RS:SP is 2:1.

This means RS is twice as long as SP. Consequently, this means the area of triangle RSQ is twice that of the area of triangle PSQ. It might help to rotate the diagram so that line PSR is horizontal and Q is above this horizontal line.

We found

area of triangle PSQ = 13.0074347717966

So,

area of triangle RSQ = 2*(area of triangle PSQ)

area of triangle RSQ = 2*13.0074347717966

area of triangle RSQ = 26.0148695435932

------------

We're onto the last step. Add up the smaller triangular areas we found

area of triangle PQR = (area of triangle PSQ)+(area of triangle RSQ)

area of triangle PQR = (13.0074347717966)+(26.0148695435932)

area of triangle PQR = 39.0223043153899

------------

<h3>Answer: 39.0223043153899</h3>

This value is approximate. Round however you need to.

===========================================

Part (b)

Focus on triangle PSQ. Let's find the length of PS.

We'll use the value of angle Q to determine this length.

We'll use the law of sines

sin(Q)/(PS) = sin(P)/(SQ)

sin(45.110237173726)/(PS) = sin(52)/(5.4)

5.4*sin(45.110237173726) = PS*sin(52)

PS = 5.4*sin(45.110237173726)/sin(52)

PS = 4.8549034284642

Because RS is twice as long as PS, we know that

RS = 2*PS = 2*4.8549034284642 = 9.7098068569284

So,

PR = RS+PS

PR = 9.7098068569284 + 4.8549034284642

PR = 14.5647102853927

-------------

Next we use the law of cosines to find RQ

Focus on triangle PQR

c^2 = a^2 + b^2 - 2ab*cos(C)

(RQ)^2 = (PR)^2 + (PQ)^2 - 2(PR)*(PQ)*cos(P)

(RQ)^2 = (14.5647102853927)^2 + (6.8)^2 - 2(14.5647102853927)*(6.8)*cos(52)

(RQ)^2 = 136.420523798282

RQ = sqrt(136.420523798282)

RQ = 11.6799196828694

--------------

We'll use the law of sines to find angle R of triangle PQR

sin(R)/PQ = sin(P)/RQ

sin(R)/6.8 = sin(52)/11.6799196828694

sin(R) = 6.8*sin(52)/11.6799196828694

sin(R) = 0.4587765387107

R = arcsin(0.4587765387107)

R = 27.3081879220073

--------------

This leads to

P+Q+R = 180

Q = 180-P-R

Q = 180-52-27.3081879220073

Q = 100.691812077992

This is the measure of angle PQR

subtract off angle PQS found back in part (a)

angle SQR = (anglePQR) - (anglePQS)

angle SQR = (100.691812077992) - (45.110237173726)

angle SQR = 55.581574904266

--------------

<h3>Answer: 55.581574904266</h3>

This value is approximate. Round however you need to.

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