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3 years ago

Which point lies on the line with point-slope equation y-3=4(x+7)

Mathematics

2 answers:

Arte-miy333 [17]3 years ago

7 0

Point slope equation for point (h,k) and slope m is given by

y-k=m(x-h)

compare given equation with formula

we get h=-7, k=3

so the required point is (-7,3)

andrew-mc [135]3 years ago

3 0

Point slope is y - y1 = m(x - x1).

m is the slope, y1 is the y coordinate, and x1 is the x coordinate.

So, the point that lies on the line in the equation is (-7, 3).

:)))

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Find perpendicular,hypotenuse and base

vova2212 [387]

Step-by-step explanation:

In right angled triangle ABC,

Taking alpha as reference angle,

By pythagoras theorem,

p=BC,h=AB,b=AC

Taking thita as reference angle,

p=AC,h=AB,b=BC

Keep smiling and hope u are satisfied with my answer.Have a good day :)

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3 years ago

50 POINTS HELP ASAP PLZ What is the equation of this line?

RSB [31]

Answer:

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2 years ago

I’m the triangle shown below what is the approximate value of x

Dafna1 [17]

Answer:

The answer is choice B: 22.52 units.

Step-by-step explanation:

We use the Pythagoras's theorem which says for a right triangle with sides $x,y$ and hypotenuse $z$ :

$x^2+y^2=z^2.$

In our case

$z=26$

$y=13$

So we solve for $x:$

$x=\sqrt{z^2-y^2}=\sqrt{26^2-13^2} =\boxed{22.52\: units.}$

Which is choice B.

8 0

3 years ago

An earthquake with a rating of 3.3 is not

stiks02 [169]

Answer:

1995.26

Step-by-step explanation:

It usually works to follow instructions:

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1995.26 = x . . . . simplify, round to hundredths

5 0

3 years ago

Determine the domain of the function (fog)(x) where f(x)=3x-1/x-4 and g(x)=x+1/x

Katarina [22]

Answer: (-∞,-1) ∪ (0,+∞)

Step-by-step explanation: The representation fog(x) is a representation of composite function, meaning one depends on the other.

In this case, fog(x) means:

fog(x) = f(g(x))

fog(x) = $3(x+\frac{1}{x} )-\frac{1}{x+\frac{1}{x} } -4$

$fog(x)=3x+\frac{3}{x} -\frac{1}{\frac{x^{2}+x}{x} } -4$

$fog(x)=3x+\frac{3}{x} -\frac{x}{x^{2}+x} -4$

$fog(x)=\frac{3x^{2}(x^{2}+x)+3(x^{2}+x)-x-4x(x^{2}+x)}{x(x^{2}+x)}$

$fog(x)=\frac{3x^{4}+3x^{3}+3x^{2}+3x-x-4x^{3}+4x^{2}}{x(x^{2}+x)}$

$fog(x)=\frac{3x^{4}-x^{3}-x^{2}+2x}{x(x^{2}+x)}$

This is the function fog(x).

The domain of a function is all the values the independent variable can assume.

For fog(x), denominator can be zero, so:

$x(x^{2}+x) \neq 0$

If x = 0, the function doesn't exist.

$x^{2}+x \neq0$

$x(x+1) \neq0$

$x+1\neq0$

$x\neq-1$

Therefore, the domain of this function is: -∞ < -1 or x > 0

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3 years ago