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lora16 [44]
3 years ago
12

What is the correct choice

Mathematics
2 answers:
Mekhanik [1.2K]3 years ago
5 0
I think it would be A. 

Maybe not because they are all negatives. 
Sliva [168]3 years ago
5 0
The answer is B. By rotating it 90 degrees counterclockwise around the origin, you will switch your x and y values, and your new x value will now be positive, so (x,y) is now (-y,x). Then, you add 4 to each y value and you are matched with answer B.
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Evaluate each function at each of the four points.
Mumz [18]

Answer:

Step-by-step explanation:

All we have to do is input the given values of x into the functions.

The first function:

f(x) = x^2 - 5x - 6

f(0) = 0^2 - 5(0) - 6 = 0 - 0 - 6 = -6

f(0) = -6

f(2) = 2^2 - 5(2) - 6 = 4 - 10 - 6 = -12

f(2) = -12

f(-1) = -1^2 - 5(-1) - 6 = 1 + 6 - 6 = 1

f(-1) = 1

f(6) = 6^2 -5(6) - 6 = 36 - 30 - 6 = 0

f(6) = 0

The second function:

f(x) = x^3 - x^2 - 12

f(0) = 0^3 - 0^2 - 12 = 0 - 0 - 12 = -12

f(0) = -12

f(2) = 2^3 - 2^2 - 12 = 8 - 4 - 12 = -8

f(2) = -8

f(-1) = -1^3 - (-1)^2 - 12 = -1 - 1 - 12 = -14

f(-1) = -14

f(6) = 6^3 - 6^2 - 12 = 216 - 36 - 12 = 168

f(6) = 168

The third function:

f(x) = 5 * 2^x

f(0) = 5 * 2^0 = 5 * 1 = 5

f(0) = 5

f(2) = 5 * 2^2 = 5 * 4 = 20

f(2) = 20

f(-1) = 5 * 2^-1 = 5 * 0.5 = 2.5

f(-1) = 2.5

f(6) = 5 * 2^6 = 5 * 64 = 320

f(6) = 320

5 0
3 years ago
When looking at a quadratic function on a graph, whether it is down or up, the domain will always be all real numbers or does it
aniked [119]

The domain of any graph depends on the vertex as well as the asymptotes. You can easily tell if the domain is all real numbers by looking at the graph and seeing that it goes clearly from -infinity to +infinity. If there is an asymptote that blocks it, then it will not be all real numbers.

7 0
3 years ago
Questions. multiple choicw
jeyben [28]
11. 8 * 18 = 144 in³, Option D

12. Half the height of 8 cm is 4 cm. Volume = 4 * 6 * 10 = 240 cm³, Option D

13. Double the dimensions you get 8 cm for the height, 6 cm for the radius. Then plug in. V = pi * (6)² * 8 >> pi * 36 * 8 = 288pi or ≈ 904.78, Option C

14. Half of all the dimensions are 1 in, 4 in, and 3 in. 1 * 4 * 3 = 12 in³, Option B

15. \frac{10}{16} =  \frac{x}{18} >> 16x = 180 >> x = 11.25 so Option B

16. Option D, 10 cm.

17. Option C, 8.5 in

18. Option B. 10.2 km

19. Option D. 0.82

20. cos 30 = b / 11.5 >> b = 11.5(cos (30)) = 9.96 m, Option C. 
6 0
3 years ago
When Mr. P. drinks an 8-ounce glass of cola, how many teaspoons of sugar is he consuming if one teaspoon of sugar provides 4 gra
natta225 [31]

The number of teaspoons of sugar that Mr. P. consumes is = 56.7 teaspoons.

<h3>Calculation of total sugar quantity</h3>

The total amount of cola taken is 8-ounce

To covert ounce to grams , the following is carried out;

1 ounce =28.35g

8 ounce = X

Xg = 8 × 28.35

X = 226.8g

But one teaspoon = 4 grams

X teaspoon = 226.8g

cross multiply to solve for x

X = 226.8g/ 4

X = 56.7 teaspoons

Therefore, the number of teaspoons of sugar that Mr. P. consumes is = 56.7 teaspoons.

Learn more about multiplication here:

brainly.com/question/10873737

4 0
2 years ago
What is the greatest common factor of 44c^5, 22c^3 and 11c^4
Alexxandr [17]

\text{ GCF of } 44c^5, 22c^3 , 11c^4 \text{ is } 11c^3

<em><u>Solution:</u></em>

Given that, we have to find the greatest common factor of 44c^5, 22c^3 , 11c^4

The greatest number that is a factor of two (or more) other numbers.

When we find all the factors of two or more numbers, and some factors are the same ("common"), then the largest of those common factors is the Greatest Common Factor

\underline{\text{ GCF of } 44c^5, 22c^3 , 11c^4 :}

First find the GCF of numbers and then find the GCF of variables and then multiply them together

<em><u>Step 1: GCF of 44, 22 and 11</u></em>

The factors of 11 are: 1, 11

The factors of 22 are: 1, 2, 11, 22

The factors of 44 are: 1, 2, 4, 11, 22, 44

11 is the greatest factor that is common in above three list

Then the greatest common factor is 11

\text{ Step 2: GCF of }c^5, c^3 , c^4

c^5 = c^3 \times c^2\\\\c^3 = c^2 \times c^1 \text{ or } c^3\\\\c^4 = c^3 \times c^1

Thus the greatest common factor is c^3

Step 3: Multiply the GCF of 44, 22, 11 and GCF of c^5, c^3 , c^4

\text{ GCF of } 44c^5, 22c^3 , 11c^4 = 11 \times c^3 = 11c^3

Thus \text{ GCF of } 44c^5, 22c^3 , 11c^4 \text{ is } 11c^3

8 0
3 years ago
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