The prove to show that the area of the shaded portion is 18x - 30 is as follows: 3x² + 13x - 30 - 3x² + 5x = 18x - 30
<h3>How to find the area of the shaded region?</h3>
The area of the shaded region can be represented as follows:
area of the shaded region = area of rectangle - area of triangle
Therefore,
area of the rectangle = (x + 6)(3x - 5)
area of the rectangle = 3x² - 5x + 18x - 30
area of the rectangle = 3x² + 13x - 30
area of triangle = 1 / 2 × 2x × 3x - 5
area of triangle = 3x² - 5x
Therefore,
area of the shaded portion = 3x² + 13x - 30 - 3x² + 5x
area of the shaded portion = 18x - 30
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Answer:
1/64 c
Step-by-step explanation:
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<span>a) Intervals of increase is where the derivative is positive
b) </span> <span>Intervals of decrease is where the derivative is negative. </span>
c) <span>Inflection points of the function are where the graph changes concavity that is the point where the second derivative is zero </span>
<span>d)
Concave up- Second derivative positive </span>
<span>Concave down- second derivative negative </span>
f(x) = 4x^4 − 32x^3 + 89x^2 − 95x + 31
<span>f '(x) = 16x^3 - 96x^2 + 178x - 95 </span>
<span>f "(x) = 48x^2 - 192x + 178 </span>
<span>By rational root theorem the f '(x) has one rational root and factors to: </span>
<span>f '(x) = (2x - 5)*(8x^2 - 28x + 19) </span>
<span>Using the quadratic formula to find it's two irrational real roots. </span>
<span>The f "(x) = 48x^2 - 192x + 178 only has irrational real roots, use quadratic formula which will be the inflection points as well.</span>
Using the formula y=200+50x, plug in x=1 to get y=250.
Answer:
Pumkins $7 and Watermelons $5
Step-by-step explanation:
let pumkins be P and watermelons be W s0
5P+20W=135 and 10P+16W=150
express first equation in terms of P
5P+20W=135
5P=135-20W (divide equation by 5)
P=27-4W
now express the second equation using the new P value
10P+16W=150
10(27-4W)+16W=150
270-40W+16W=150
120=24W
W=5
now plug in w value and solve for p
5P+20(5)=135
P=7
