Answer:
if you increase by 4%, it means you will have a new total of 104%. In decimals it is 1.04 (divide your percentage by 100) after that you do the same with the 3% increase. you'll have a new total of 103%. In decimals 1.03. If you want to know what single multiplier you can use, you need to multiply the both decimals. So you get 1.04 x 1.03 = 1.0712
Step-by-step explanation:
Answer:

Step-by-step explanation:
Given

Required
Determine the test statistic
Let the dataset of stick be A and Liquid be B.
We start by calculating the mean of each dataset;

n, in both datasets in 6
For A



For B



Next, calculate the sample standard deviation
This is calculated using:

For A




For B




Calculate the pooled variance




Lastly, calculate the test statistic using:

We set

So, we have:


The equation becomes




<em>The test statistic is 31.29</em>
Answer:
12
Step-by-step explanation:
Just add them lol
Answer:
The answer would be (-2, -5)
Step-by-step explanation:
3x - 8y= 34
2(7x + 4y = -34)
3x - 8y=34
14x + 8y= -68
----------------------
17x= -34 divided by 17
x = -2
3(-2) -8y= 34
-6 -8y =34 add 6
-8y= 40 divide by -8
y = -5
if you want to check the answer replacing -2 for x and -5 for y
7(-2) + 4(-5)= -34
-14 + (-20) = -34
-34 = -34
I hope this help sorry I'm not good explaining
Answer:
Positive
Step-by-step explanation:
Since there are two x-intercepts, -2 and 2, there is a positive discriminant. If the parabola was below the x axis and opened downwards, the discriminant would be negative.