Answer:
6,04x10⁻³M
Explanation:
For the reaction:
Fe(s) + CuSO₄(aq) → Cu(s) + FeSO₄(aq)
The precipitate of Cu(s) weights 96,0 mg. In moles:
Moles of Cu(s):
0,096g×(1mol/63,546g) = 1,51x10⁻³ moles of Cu(s). If you see the balanced equation 1 mole of CuSO₄ produce 1 mole of Cu(s). That means moles of CuSO₄ are the same of Cu(s), <em>1,51x10⁻³ moles of CuSO₄</em>
As volume of the solution is 250 mL, 0,250L, the molar concentration of the original solution is:
1,51x10⁻³ moles of CuSO₄ / 0,250L = <em>6,04x10⁻³M</em>
I hope it helps!
Answer is: 12 grams of the isotope carbon-12 (¹²C).
The Avogadro’s number is the number of atoms in 12 grams of the isotope carbon-12 (¹²C).
Na is Avogadro number or Avogadro constant (the number of particles, in this example carbon, that are contained in the amount of substance given by one mole).
The Avogadro number has value 6.022·10²³ 1/mol in the International System of Units; Na = 6.022·10²³ 1/mol.
Answer:
A single bond between two atoms corresponds to the sharing of one pair of electrons. Two hydrogen atoms can then form a molecule, held together by the shaped pair of electrons. Each H atom now has the Noble gas electron configuration of helium ( He). The pair of shared electrons forms a single covalent bond.
