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Triss [41]
3 years ago
15

Describe two ways he could change the metal physically and two ways he could change the metal chemically to try to identify it.

Chemistry
1 answer:
slega [8]3 years ago
6 0
Physical change is a change that occurs in a substance that does not change the identity of the substance. It does not alter the chemical structure of the molecules ehile chemical change involves the breaking of the bonds in the substance forming new substance. To identify a metal physically, we can use properties like their boiling and melting points. We can determine at what temperatures these metals melt or boil then from literature we compare the values. Another properties that can be looked upon to are hardness, color and density. For chemical methods, we can allow it to react with substances, that will produce precipitates containing the metal in question. Also, we can use other methods like titration method. All chemical methods involves the use of chemical reactions.
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Determine the volume of occupied by 4 moles of carbon dioxide gas at
valentina_108 [34]

Answer:

Vol of 4 moles CO₂(g) at STP = 89.6 Liters

Explanation:

STP

P = 1 Atm

V =

T = 0°C = 273 K

n = 4 moles

R = 0.08206 L·Atm/mol·K

Using Ideal Gas Law PV = nRT => V = nRT/P

V = (4 moles)(0.08206 L·Atm/mol·K)(273 K)/(1 Atm) = 89.6 Liters

5 0
3 years ago
A student balanced the chemical equation Mg + O2 →MgO by writing Mg + O2 → MgO2. Was the equation balanced correctly? Explain yo
Amanda [17]

Explanation:

Charges on both magnesium and oxygen is 2. Though opposite in sign, they have equal charges so, both of them will be cancelled by each other.

As a result, formula of magnesium oxide is MgO and not MgO_{2}.

The student write the equation as Mg + O_2 \rightarrow MgO_2, it is not correct.

Therefore, given equation will be balanced as follows.

          2Mg + O_{2} \rightarrow 2MgO

Since, number of atoms on both reactant and product side are equal. Hence, this equation is completely balanced.

7 0
3 years ago
Exercise 2:
vagabundo [1.1K]

Answer:

1. KCLO3------>KCL + 3/2O2(g)

2. 122.5g/mol

3. 0.2mol

4. 18.5g

7 0
3 years ago
True or false. (Pls help)
grigory [225]
I believe they’re both true.
5 0
3 years ago
Read 2 more answers
Write the reaction that occurs when propyl methanoate is hydrolyzed in water and in NaOH
Free_Kalibri [48]

An ester , propyl methanoate ( HCOOC₃H₇) when reacts with sodium hydroxide( NaOH) forms sodium methanoate (HCOONa) as the main product and propanol (C₃H₇OH).

The reaction is as follows:

HCOOC₃H₇+NaOH ⇒HCOONa + C₃H₇OH

So when propyl methanoate is hydrolyzed in water and in NaOH then sodium methanoate (HCOONa) as the main product and propanol (C₃H₇OH) forms

5 0
3 years ago
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