Sqrt(18x^5y) + sqrt(32xy^3) - sqrt(128xy)
You may separate the roots to produce solvable square roots!
sqrt(9x^4)*sqrt(2xy) + sqrt(16y^2)*sqrt(2xy) - sqrt(64)*sqrt(2xy)
Simplifying makes it ...
(3x^2 + 4y - 8)*sqrt(2xy)
This should be the closest you can get to a simplified equation.
South west
Shifting 4 units left (decreasing in x-axis by 4 units)
Shifting 5 units down (decreasing in y-axis by 5 units)
Apply to every vertices coordinates(x - 4, y - 5)
New coordinates
A(-2, -1)
B(-1, -4)
C(1,0)
1/2. You would round 3/8 to 1/2 to 0. Then you add 1/2 to 0 and you get your answer.
Answer:
80/81
Step-by-step explanation:
If a head is twice as likely to occur as a tail, then the probability of getting heads is 2/3 and the probability of getting tails is 1/3.
The probability of getting at least 1 head involves 4 scenarios:
1) 1 Head and 3 Tails
2) 2 Heads and 2 Tails
3) 3 Heads and 1 Tail
4) 4 Heads
Instead of calculate all these scenarios, you could calculate the opposite scenario: 4 Tails. The sum of all possible scenarios is 1, so:
P(at least one head) + P(no heads) = 1
Then, P(at least one head) = 1 - P(no heads)
The probability of 4 tails is:
P(no heads) = P(TTTT) = (1/3)(1/3)(1/3)(1/3)=1/81
Then, P(at least one head) = 1 - 1/81=80/81
First do the the parenthesis: (6-3) = 3
Now you have [-4 + 3 * 8] -10
Next do multiplication: 3 *8 = 24
Now you have [-4 + 24]-10
Now do what is in brackets: -4 + 24 = 20
Now you have 20-10
Subtract 20-10 = 10
