M<3 = m<5
10x = 12x - 25
2x = 25
x = 12.5
answer is A. first choice
Answer:Multiply 410,000 with 26:)
Step-by-step explanation:
Answer:
y=.5x-2
Step-by-step explanation:
If one line is perpendicular to another that means that their slopes are negative reciprocals
which means that the slope (or m in y=mx+b) is .5
so far we have
y=.5x+b
to solve for b we plug in (8,2)
2=.5(8)+b
2=4+b
-2=b
therefore our equation is
y=.5x-2
Answer:

Step-by-step explanation:
The probability of matching the number drawn on the gold ball is

The number of possible pairs of numbers from 1 to 53 is

Choosing 5 numbers, you are choosing 10 different pairs:

Therefore the probability of correctly matching the drawn pair is

Thus, the probability of winning (matching the pair AND the gold ball) is

Answer:
Vertical A @ x=3 and x=1
Horizontal A nowhere since degree on top is higher than degree on bottom
Slant A @ y=x-1
Step-by-step explanation:
I'm going to look for vertical first:
I'm going to factor the bottom first: (x-3)(x-1)
So we have possible vertical asymptotes at x=3 and at x=1
To check I'm going to see if (x-3) is a factor of the top by plugging in 3 and seeing if I receive 0 (If I receive 0 then x=3 gives me a hole)
3^3-5(3)^2+4(3)-25=-31 so it isn't a factor of the top so you have a vertical asymptote at x=3
Let's check x=1
1^3-5(1)^2+4(1)-25=-25 so we have a vertical asymptote at x=1 also
There is no horizontal asymptote because degree of top is bigger than degree of bottom
There is a slant asympote because the degree of top is one more than degree of bottom (We can find this by doing long division)
x -1
--------------------------------------------------
x^2-4x+3 | x^3-5x^2+4x-25
- ( x^3-4x^2+3x)
--------------------------------
-x^2 +x -25
- (-x^2+4x-3)
---------------------
-3x-22
So the slant asymptote is to x-1