Modular arithmetic is all about finding the remainder from long division (MOD), and the total number of times that a number goes into a division (DIV<span>).</span>
Answer:
60years
Step-by-step explanation:
let Ben age = x
ishaan age = y
Ben is 4 times old as ishaan:
x=4y ..........equation (1)
6 years ago
Ben age = x-6
Ishaan age = y-6
x-6=6(y-6)
x-6=6y-36
x=6y-36+6
x=6y-30..........equation (2)
equating equation(1) and (2)
4y=6y-30
4y-6y=-30
-2y=-30
y=-30/-2=15
substituting the value of y into equation (1)
x=4y
=4*15
=60
Ben age now =60years
Answer: Choice B. k(h(g(f(x))))
For choice B, the functions are k, h, g, f going from left to right.
===========================================================
Explanation:
We have 4x involved, so we'll need f(x)
This 4x term is inside a cubic, so we'll need g(x) as well.
So far we have
g(x) = x^3
g( f(x) ) = ( f(x) )^3
g( f(x) ) = ( 4x )^3
Then note how we are dividing that result by 2. That's the same as applying the h(x) function

And finally, we subtract 1 from this, but that's the same as using k(x)

This leads to the answer choice B.
To be honest, this notation is a mess considering how many function compositions are going on. It's very easy to get lost. I recommend carefully stepping through the problem and building it up in the way I've done above, or in a similar fashion. The idea is to start from the inside and work your way out. Keep in mind that PEMDAS plays a role.
Answer:
Step-by-step explanation:
its B