Please help me w dis asap!!!

Mathematics

1 answer:

just olya [345]2 years ago

3 0

Answer & Step-by-step explanation:

In order to solve this problem, it's important that we look at the tiles and the the signs that are in front of them. The top row of tiles represents our first expression and the bottom row of tiles represents our second equation.

The two large tiles are positive so they are going to be positive in our equation.

(x² ) - (-x² )

The four blue rectangle tiles are also positive, so they are going to be positive in our equation. The two red rectangle tiles are negative, so they are going to be negative in out equation.

(x² + 4x) - (-x² + 2x)

The two red square tiles are negative, so they are going to be negative in our equation. The four blue square tiles are positive, so they are going to be positive in our equation.

(x² + 4x - 2) - (-x² + 2x - 4)

So, your answer is going to be letter choice C.

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Ex 4.8<br> 14) integrate 3^(2x-1)

sesenic [268]

Take the integral:

$\large\begin{array}{l} \mathsf{\displaystyle\int\!3^{2x-1}\,dx}\\\\ =\mathsf{\displaystyle\int\!\frac{1}{2}\cdot 2\cdot 3^{2x-1}\,dx}\\\\ =\mathsf{\displaystyle\frac{1}{2}\int\!3^{2x-1}\cdot 2\,dx\qquad(i)} \end{array}$

$\large\begin{array}{l} \textsf{Substitute}\\\\ \mathsf{2x-1=u\quad\Rightarrow\quad 2\,dx=du}\\\\\\ \textsf{so (i) becomes}\\\\ =\mathsf{\displaystyle\frac{1}{2}\int\!3^u\,du}\\\\ =\mathsf{\dfrac{1}{2}\cdot \dfrac{1}{\ell n\,3}\,3^u+C}\\\\ =\mathsf{\dfrac{1}{2\,\ell n\,3}\,3^{2x-1}+C} \end{array}$

$\large\begin{array}{l} \boxed{\begin{array}{c}\mathsf{\displaystyle\int\!3^{2x-1}\,dx=\frac{1}{2\,\ell n\,3}\,3^{2x-1}+C} \end{array}}\qquad\checkmark \end{array}$

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$\large\textsf{I hope it helps. :-)}$
</span>

Tags: <em>integrate indefinite integral substitution exponential base logarithm log ln composite integral calculus

</em>

4 0

3 years ago

andre has 4 times as many model cars as Peter , and Peter has one-third as many model cars as jade . andre has 36 model cars . a

lorasvet [3.4K]

P = how many cars Peter has
j = how many cars Jade has
a = how many cars Andre has
p x 4 = how many cars Andre has (36 model cars)
>>>TO FIND HOW MANY MODEL CARS PETER HAS:
p x 4 = 36
36 / 4 = 9
your equation to find how many model cars Peter has is:
36 / 4 = 9
So, Peter has 9 model cars.
>>>TO FIND HOW MANY MODEL CARS JADE HAS:
36 / 4 = how many cars Peter has (9)
Now, you are given the info that Jade has THREE TIMES (3x) as many cars as Peter already.
So, your equation for this one is:
9 x 3 = 27
So Jade has 27 model cars.

---- Jade has 27 model cars.
---- Andre has 36 model cars.
---- Peter has 9 model cars.

equation for a. 36 / 4 = p
equation for b. 9 x 3 = j

3 0

3 years ago

Read 2 more answers

Given y=-3/4x-2. What is the equation of the line that is perpendicular and has the point (-4,1)? Write answer in slope intercep

raketka [301]

Answer:

y=4/3+19/3

Step-by-step explanation:

When it asks for perpendicular it means your focusing on the slope.

Perpendicular means opposite of the current slope, so flip it and change the sign (-3/4 changes to 4/3). Next you will use the equation (y-y1)=m(x-x1)

y1=the y value given

x1=the x value given

m=your slope

(y-1)=4/3(x+4) Since the x point is minus a negative we get to change the sign to a positive. Next distribute the 4/3 to each term in the parenthesis.

y-1=4/3(x)+4/3(4)

y-1=4/3x+16/3 Now we add the one to both sides.

+1 +1 The one isn't in teh correct format to just add so first imagine it as 1/1. Now to get the bottom to have a 3 like in 16/3 we just multiply the top and bottom by 3.

$\frac{1}{1} x\frac{3}{3}=\frac{3}{3}$ Now we can add this to the 16/3