The specific gravity is the ratio of the density of oil to the density of water. Since the density of water is 1g/ml, the density of a substance is numerically the same as the specific gravity.
However, specific gravity is a dimensionless number, while density has units mass/volume.
So, the density of oil is .901 g/ml, but the specific gravity is just .901
In Imperial units, the density of the oil is 56.2 lb/ft^3, but the specific gravity is still .901
F = force applied to stop the car = - 3000 N
m = mass of the car = 3000 kg
a = acceleration of the car = ?
v₀ = initial velocity of the car before the force is applied to stop it = 10 m/s
v = final velocity of the car when it comes to stop = 0 m/s
d = stopping distance of the car
acceleration of the car is given as
a = F/m
inserting the values
a = - 3000/3000
a = - 1 m/s²
using the kinematics equation
v² = v²₀ + 2 a d
inserting the values
0² = 10² + 2 (-1) d
0 = 100 - 2 d
2 d = 100
d = 100/2
d = 50 m
hence the correct choice is
C. 50 m
Answer:
3.1m
Explanation:
Since we only care about the y direction we only need to find vy. Once u draw your vector you will realize that vy= 4.5sin60=3.897m/s.
use vf²=v²+2a(y)
At the maximum height the velocity is 0 and since the object is in freefall, a=-g
Plug in all values
0=15.1875-2*9.8(y)
solve for y
-15.1875*2/-9.8=y
y=3.1m
The reverse of deposition is sublimation and hence sometimes deposition is called desublimation. One example of deposition is the process by which, in sub-freezing air, water vapor changes directly to ice without first becoming a liquid.
The magnitude of gravity is expressed in terms of its acceleration. So the magnitude of ' g ' at that altitude is exactly 6.5 m/s^2.
