Answer:
B) Diphosphorus pentoxide
Explanation:
Answer: 2812500 joules
Explanation:
Mass of car = 1500kg
Velocity of car = 75mph
Kinetic energy = ?
Recall that kinetic energy is the energy possessed by a moving object, and it depends on its mass M and velocity, V
Thus, Kinetic energy = 1/2 x mv^2
= 1/2 x 1000kg x (75mph)^2
= 0.5 x 1000kg x (75mph)^2
= 500 x 5625
= 2812500 joules
Thus, the car travels with a kinetic energy of 2812500 joules
Harnessing the sun's energy to produce heat or electricity is : A. Non - Polluting
This energy generating method will cause no dangerous emission for environment (unlike the one that came from fossil fuel), but the energy that produced from the sun tend to be more expensive so it's still not widely used
hope this helps
Answer:
<h2><u>Given </u><u>:</u><u>-</u></h2>
- Mass = 1025 kg
- Acceleration = 9.8 m/s²
<h2><u>To </u><u>Find</u><u> </u><u>:</u><u>-</u></h2>
Force
<h2><u>Solution</u><u> </u><u>:</u><u>-</u></h2>
We know that
F = mg
F = 1025 × 9.8
F = 10,045 N
Or,
10045/1000 = 10.045 Kilo Newton
![\\](https://tex.z-dn.net/?f=%20%5C%5C%20)
Answer:
![\rho_{s} = 4](https://tex.z-dn.net/?f=%5Crho_%7Bs%7D%20%3D%204%20)
![\rho_{l} = 0.6](https://tex.z-dn.net/?f=%5Crho_%7Bl%7D%20%3D%200.6%20)
![\rho{liq} = 600 kg/m^{3}](https://tex.z-dn.net/?f=%5Crho%7Bliq%7D%20%3D%20600%20kg%2Fm%5E%7B3%7D)
Given:
Weight of solid in air, ![w_{sa} = 200 N](https://tex.z-dn.net/?f=w_%7Bsa%7D%20%3D%20200%20N)
Weight of solid in water, ![w_{sw} = 150 N](https://tex.z-dn.net/?f=w_%7Bsw%7D%20%3D%20150%20N)
Weight of solid in liquid, ![w_{sl} = 170 N](https://tex.z-dn.net/?f=w_%7Bsl%7D%20%3D%20170%20N)
Solution:
Calculation of:
1. Relative density of solid, ![\rho_{s}](https://tex.z-dn.net/?f=%5Crho_%7Bs%7D)
![\rho_{s} = \frac{w_{sa}}{w_{sa} - w_{sw}}](https://tex.z-dn.net/?f=%5Crho_%7Bs%7D%20%3D%20%5Cfrac%7Bw_%7Bsa%7D%7D%7Bw_%7Bsa%7D%20-%20w_%7Bsw%7D%7D)
![\rho_{s} = \frac{200}{200 - 150} = 4](https://tex.z-dn.net/?f=%5Crho_%7Bs%7D%20%3D%20%5Cfrac%7B200%7D%7B200%20-%20150%7D%20%3D%204%20)
2. Relative density of liquid, ![\rho_{l}](https://tex.z-dn.net/?f=%5Crho_%7Bl%7D)
![\rho_{l} = \frac{w_{sa} - w_{sl}}{w_{sa} - w_{sw}}](https://tex.z-dn.net/?f=%5Crho_%7Bl%7D%20%3D%20%5Cfrac%7Bw_%7Bsa%7D%20-%20w_%7Bsl%7D%7D%7Bw_%7Bsa%7D%20-%20w_%7Bsw%7D%7D)
![\rho_{l} = \frac{200 - 170}{200 - 150} = 0.6](https://tex.z-dn.net/?f=%5Crho_%7Bl%7D%20%3D%20%5Cfrac%7B200%20-%20170%7D%7B200%20-%20150%7D%20%3D%200.6)
3. Density of liquid in S.I units:
Also, we know:
![\rho{l} = \frac{\rho_{liq}}{\rho_{w}}](https://tex.z-dn.net/?f=%5Crho%7Bl%7D%20%3D%20%5Cfrac%7B%5Crho_%7Bliq%7D%7D%7B%5Crho_%7Bw%7D%7D)
where
= density of liquid
= density of water
Now, from the above formula:
![0.6 = \frac{\rho_{liq}}{1000}](https://tex.z-dn.net/?f=0.6%20%3D%20%5Cfrac%7B%5Crho_%7Bliq%7D%7D%7B1000%7D)
![\rho{liq} = 600 kg/m^{3}](https://tex.z-dn.net/?f=%5Crho%7Bliq%7D%20%3D%20600%20kg%2Fm%5E%7B3%7D)