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Sati [7]
3 years ago
11

what is the magnitude of g at a height above earth surface where free fall acceleration equal 6.5m/s2

Physics
1 answer:
ZanzabumX [31]3 years ago
8 0
The magnitude of gravity is expressed in terms of its acceleration. So the magnitude of ' g ' at that altitude is exactly 6.5 m/s^2.
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Vesnalui [34]

Answer:

<em>The comoving distance and the proper distance scale</em>

<em></em>

Explanation:

The comoving distance scale removes the effects of the expansion of the universe, which leaves us with a distance that does not change in time due to the expansion of space (since space is constantly expanding). The comoving distance and proper distance are defined to be equal at the present time; therefore, the ratio of proper distance to comoving distance now is 1. The scale factor is sometimes not equal to 1. The distance between masses in the universe may change due to other, local factors like the motion of a galaxy within a cluster.  Finally, we note that the expansion of the Universe results in the proper distance changing, but the comoving distance is unchanged by an expanding universe.

4 0
3 years ago
The near point of a farsighted person's uncorrected eyes is 80 cm. what power contact lens should be used to move the near point
makvit [3.9K]
To solve this problem, we will get f and then we will use it to calculate the power.

So, for this farsighted person,
do = 25 cm and di = -80
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1/f = (1/25) + (1/-80) = 0.00275 = 0.275 m

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5 0
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RUDIKE [14]
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