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saw5 [17]
3 years ago
6

Is a satellite orbiting earth free from earths gravity ? Why or why not

Physics
2 answers:
marysya [2.9K]3 years ago
8 0
No, because gravitational fields go on forever.

Westkost [7]3 years ago
7 0
No . . . the earth's gravitational force is a requirement of the satellite maintaining orbit around the planet . . . without it, you could expect the satellite to just float on being earth like a comet passing by
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Dos cargas Q1=2pc y Q2=4pc estan separadas por una distancia de 6cm ¿con que fuerza se atraen?
noname [10]

Here we can use coulomb's law to find the force between two charges

As per coulombs law

]tex]F = \frac{kq_1q_2}{r^2}[/tex]

here we have

k = 9 * 10^9

q_1 = 2pC

q_2 = 4pC

r = 6cm = 0.06 m

now by using the above equation we have

F = \frac{9*10^9 * 2*10^{-12} * 4*10^{-12}}{0.06^2}

F = 2 * 10^{-11} N

so here the force between two charges is of above magnitude and this will be repulsive force between them as both charges are of same sign.

3 0
3 years ago
You run away from a plane mirror at 2.30 m/s. At what speed does your image move away from you?
ivanzaharov [21]

Answer:

4.60m/s

.............

5 0
3 years ago
Background information about reflection and refraction of light
KIM [24]

Answer:

reflection :

  • angle of reflection and angle of incidence is equal
  • Incident ray and reflect d ray plus normal lies on the same plan on a same point
  • light reflect uniformly if it is incident on a plan surface

refraction :

  • light will refrect if light goes from rare medium to a dense medium or vice versa
  • after the light is refracted, it retunes to its original direction
  • angle of incidence is not equal to the angle of refraction
4 0
3 years ago
What type of tide occurs when the sun, moon, and earth form a right triangle in space?
stiks02 [169]
Neap tide is your answer
7 0
3 years ago
A pipe that is open at both ends has a fundamental frequency of 320 Hz when the speed of sound in air is 331 m/s.
fenix001 [56]

Question

What is the length of the pipe?

Answer:

(a) 0.52m

(b) f2=640 Hz and f3=960 Hz

(c) 352.9 Hz

Explanation:

For an open pipe,  the velocity is given by

v=\frac {2Lf}{n}

Making L the subject then

L=\frac {nV}{2f}

Where f is the frequency,  L is the length,  n is harmonic number,  v is velocity

Substituting 1 for n,  320 Hz for f and 331 m/s for v then

L=\frac {1*331}{2*320}=0.5171875\approx 0.52m

(b)

The next two harmonics is given by

f2=2fi

f3=3fi

f2=3*320=640 Hz

f3=3*320=960 Hz

Alternatively, f2=2\times \frac {v}{2L} and f3=3\times \frac {v}{2L}

f2=2\times \frac {331}{2*0.52}=636.5 Hz\\f3=3\times \frac {331}{2*0.52}=954.8 Hz

(c)

When v=367 m/s then

f1= \frac {v}{2L}\\f1= \frac {367}{2*0.52}=352.9 Hz

5 0
3 years ago
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