<h2>FOLLOW ME FOR CLEARING YOUR NEXT DOUBT </h2>
True or false please help
1 answer:
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In place of t, or theta, I'm going to utilize x instead. So the equation is -3*cos(x) = 1. Get everything to one side and we have -3*cos(x)-1 = 0
Let f(x) = -3*cos(x)-1. The goal is to find the root of f(x) in the interval [0, 2pi]
I'm using the program GeoGebra to get the task done of finding the roots. In this case, there are 2 roots and they are marked by the points A and B in the attachment shown
A = (1.91, 0)
B = (4.37, 0)
So the two solutions for theta are
theta = 1.91 radians
theta = 4.37 radians
Let f(x) = -3*cos(x)-1. The goal is to find the root of f(x) in the interval [0, 2pi]
I'm using the program GeoGebra to get the task done of finding the roots. In this case, there are 2 roots and they are marked by the points A and B in the attachment shown
A = (1.91, 0)
B = (4.37, 0)
So the two solutions for theta are
theta = 1.91 radians
theta = 4.37 radians
Answer:
See explanation
Step-by-step explanation:
Jimmy is incorrect.
Using long division, you can find that the real answer.
First, subtract from the original expression, leaving you with
.
Next, subtract from the expression, leaving you with
. Finally, subtract
from the expression, leaving you with a remainder of 0. This means that the real quotient is
. Hope this helps!