Answer:
6.24 x 10-3 M
Explanation:
Hello,
In this case, for the given dissociation, we have the following equilibrium expression in terms of the law of mass action:
![Ka=\frac{[H_3O^+][BrO^-]}{[HBrO]}](https://tex.z-dn.net/?f=Ka%3D%5Cfrac%7B%5BH_3O%5E%2B%5D%5BBrO%5E-%5D%7D%7B%5BHBrO%5D%7D)
Of course, water is excluded as it is liquid and the concentration of aqueous species should be considered only. In such a way, in terms of the change 
, we rewrite the expression considering an ICE table and the initial concentration of HBrO that is 0.749 M:
Thus, we obtain a quadratic equation whose solution is:
Clearly, the solution is 0.00624 M as no negative concentrations are allowed, so the concentration of BrO⁻ is 6.24 x 10-3 M.
Best regards.
Complete Question
The diagram of the complete question is shown on the first uploaded image.
Answer:
a) The approximate absorbance of benzoic acid at 228 nm? : A = 0.8
b) The molar absorptivity(∈)
of benzoic acid at 228 nm? : ∈ = 
Explanation:
Looking at the absorbance spectra, we can see that the approximate absorbance of benzoic acid at 228 is 0.8.
mass concentration of benzoic acid = 
the molar concentration of benzoic acid = (mass concentration of benzoic acid) / (molar mass of benzoic acid )
molar concentration of benzoic acid = 
molar concentration of benzoic acid = 
molar absorptivity (∈) of benzoic acid = (absorbance) /[ (molar concentration of benzoic acid ) × (path length) ]
∈ = (0.8) / [ (
) ×(1.00 cm)]
=
That would be 23.5 degrees
As we know that
P.E. = mgh
where,
P.E. = Potential energy of the object =?
m= mass of object= 3kg
g= acceleration due to gravity = 9.8 ms^-2
h = height between object and animal = 0 m
Then
P.E. = 3× 9.8 × 0 = 0 Joules or 0J
<em>Have a luvely day!</em>
Here we have to get the item which has more thermal energy among the given options.
The item a) will have more thermal energy than b)
The thermal energy of a compound can be determined from the formula H = m×s×t (H = thermal energy, m = mass of the compound, s = specific heat of the compound, t = temperature)
a) Here m = 500 g, s = 1 g/mL and t = 50⁰C (as the density of water is 1 g/mL thus its volume is equivalent to its mass)
Thus the thermal energy H = 500 × 1 × 50 = 25000 Cal (The energy needed to raise 1⁰C temperature of 1g water is calorie unit)
similarly,
b) Here m = 100 g, s = 1 g/mL and t = 50⁰C (as the density of water is 1 g/mL thus its volume is equivalent to its mass)
Thus the thermal energy H = 100 × 1 × 50 = 5000 Cal (The energy needed to raise 1⁰C temperature of 1g water is calorie unit).
Thus option a) i.e. 500 mL of water at 50 degree Celsius will have more thermal energy.
Thus the thermal energy of both the item have calculated and compared.
