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mojhsa [17]
2 years ago
12

Under what conditions do real gases behave most ideally.

Chemistry
1 answer:
katrin [286]2 years ago
3 0

Answer:

Under high temperatures and low pressure, gases behave the most ideal.

Explanation:

Low pressure reduces the effect of the finite size of real particles by increasing the volume around each particle, and a high temperature gives enough kinetic energy to the particles to better overcome the attractions that exist between real particles. (Prevents sticking.)

In summary, real gases behave more like ideal gases when they are far away from a phase boundary, (condensation or freezing).

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1. How is the atom count for each element on the reactant side of a balanced chemical equation related to the atom count for eac
lbvjy [14]

Answer: The atom count for each element on the reactant side of a balanced chemical equation is equal to the atom count for each element on the product side of the same equation

Explanation:

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products formed must be equal to the mass of reactants taken.

In order to get the same mass on both sides, the atoms of each element must be balanced on both sides of the chemical equation.

2H_2+O_2\rightarrow 2H_2O

Thus there are 4 atoms of hydrogen on reactant as well as product side.

Also there are 2 atoms of oxygen on reactant as well as product side.

5 0
3 years ago
Pls help me with is question.​
Dennis_Churaev [7]

Answer:

25cm³ = 0.025L of H2So4

Molarity of H2SO4 = 1moldm-³

Recall ... 1dm-³ = 1L

So the Molarity can also be 1mol/L

Mole = Molarity x volume in L

Mole of H2SO4 = 1mol/L x 0.025L

=0.025Moles of Sulphuric acid reacted.

From the equation of reaction

1mole of H2SO4 reacts to produce 1mole of Copper sulphate crystal

Since their Mole ratio is 1:1

It means that Since 0.025mole of H2SO4 reacted.... 0.025mole of CuSO4.5H2O would be produced

Nice.. OK

So we know the moles of CuSO4.5H2O produced

We can get the Mass

Recall

From

Mole=Mass/Molar Mass

Mass = Mole x Molar Mass

Molar Mass of CuSO4.5H2O = 64 + 32 + 16x4+ 5(2+16)

Mm= 250g/mol

Mass = 0.025mol x 250g/mol

= 6.25g of CuSO4.5H2O crystals Would be PRODUCED.

5 0
3 years ago
Chlorine and oxygen are both gases at room temperature. What are some characteristic properties of chlorine that distinguish it
AVprozaik [17]

Answer:

A soft metal, it's solid. Chlorine and oxygen are both gases at room temperature. What are some characteristic properties of chlorine that distinguish it from oxygen? It dissolves in water.

6 0
3 years ago
Read 2 more answers
Calculate the molality of a solution containing 257 g glucose (c6h12o6) dissolved in 1.62 l of water. assume a density of 1.00 g
Alex777 [14]
Molality is defined as the number of moles of solute in 1 kg of solvent.
since density and volume has been given we can calculate the mass of water
mass = density x volume
mass = 1.00 g/mL x 1620 mL = 1620 g
number of moles of glucose - 257 g / 180 g/mol = 1.43 mol
number of moles of glucose in 1620 g - 1.43 mol
therefore number of moles in 1000 g - 1.43 mol / 1.620 kg = 0.883 mol/kg
therefore molality is 0.883 mol/kg
4 0
4 years ago
How many grams of water are produced from reacting 25 grams of oxygen gas with hydrogen gas to produce water?
Serhud [2]

Answer:

take these as notes ig:)

Explanation:

reaction equations to make connections between the reactants and products in reactions. ... pathway: mol of O2 → mol of H2O → grams of H2O. 3.5 mol ... 25 g KClO3 ... How many grams of hydrogen gas are produced from the reaction of 221.

6 0
3 years ago
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