use the identity below to complete the tasks a^3-b^3=(a-b)(a^2+ab+b^2) when using the identity for the difference of two cubes t
o factor 64x^6-27
2 answers:
Answer:
see explanation
Step-by-step explanation:
Given that the the difference of cubes is
a³ - b³ = (a - b)(a² + ab + b²)
Given
64
- 27 ← a difference of cubes
with a = 4x² and b = 3, thus
= (4x²)³ - 3³
= (4x² - 3)(16
+ 12x² + 9) ← in factored form
Answer:
Since both terms are perfect cubes, factor using the difference of cubes formula,
a
^3
−b
^3
=
(
a
−
b
)
(
a^
2
+
a
b
+
b
^2
) where a
=
4
x
2 and b
=
3
(
4
x
2
−
3
)
(16
x
4
+
12
x
2+
9
)
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