Question

use the identity below to complete the tasks a^3-b^3=(a-b)(a^2+ab+b^2) when using the identity for the difference of two cubes to factor 64x^6-27

Answer 1

Answer:

see explanation

Step-by-step explanation:

Given that the the difference of  cubes is

a³ - b³ = (a - b)(a² + ab + b²)

Given

64$x^{6}$ - 27 ← a difference of cubes

with a = 4x² and b = 3, thus

= (4x²)³ - 3³

= (4x² - 3)(16$x^{4}$ + 12x² + 9) ← in factored form

Answer 2

Answer:

Since both terms are perfect cubes, factor using the difference of cubes formula,  

a ^3 −b ^3 = ( a − b ) ( a^ 2 + a b + b ^2 )  where  a = 4 x 2  and  b = 3

( 4 x 2 − 3 ) (16 x 4 + 12 x 2+ 9 )