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2 years ago

Solve for x. 4x +15 > 23

Mathematics

2 answers:

masha68 [24]2 years ago

4 0

Answer: x > 2

Step-by-step explanation:

First, you need to isolate the variable by subtracting each side by 15.

4x + 15 > 23

-15 -15

= 4x > 8

To get the value for the variable, divide each side by 4.

4x/4 = x 8/2 = 2

x>2

oksano4ka [1.4K]2 years ago

4 0

Answer:

Step-by-step explanation:

4x + 15 > 23

4x > 8

x > 2

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The difference between 22 and x

lukranit [14]

Answer:

22-x

Step-by-step explanation:

you dont know what x is, so you would just do 22-x

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2 years ago

Two cars got an oil change at the same auto shop. The shop charges customers for each quart of oil plus a flat fee for labor. Th

zvonat [6]

The labor fee is $13.55 and each quart of oil is $2.25

Step-by-step explanation:

Let,

x be the amount of each quart of oil

y be the amount of labor fee

According to given statement;

5x+y=24.80 Eqn 1

7x+y=29.30 Eqn 2

Subtracting Eqn 1 from Eqn 2

$(7x+y)-(5x+y)=29.30-24.80\\7x+y-5x-y=4.50\\2x=4.50$

Dividing both sides by 2

$\frac{2x}{2}=\frac{4.50}{2}\\x=2.25$

Putting x=2.25 in Eqn 1

$5(2.25)+y=24.80\\11.25+y=24.80\\y=24.80-11.25\\y=13.55$

The labor fee is $13.55 and each quart of oil is $2.25

Keywords: linear equation, subtraction

Learn more about subtraction at:

#LearnwithBrainly

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2 years ago

What is estimate 4.23-2.51

ruslelena [56]

The answer is 1.72 and it would be 2 if u estimated

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3 years ago

Read 2 more answers

Assume that in a particular military exercise involving two units, Red and Blue, thereis a 60 % chance that the Red unit will su

Marysya12 [62]

Answer: a) There are 42% chances that both units will meet their objectives.

b) There are 88% chances that one or the other but not both of the units will be successful.

Step-by-step explanation:

Since we have given that

Probability that the Red unit will successfully meet its objectives = 60% = P(R)

Probability that Blue unit will successfully meet its objectives = 70% = P(B)

Probability that only Red unit will be successful = P(only Red) = 18%

As we know that

$P(only\ red)=P(R)-P(R\cap B)\\\\0.18=0.60-P(R\cap B)\\\\0.18-0.60=-P(R\cap B)\\\\-0.42=-P(R\cap B)\\\\P(R\cap B)=42\%$

Hence, there are 42% chances that both units will meet their objectives.

the probability that one or the other but not both of the units will be successful is given by

$P(R\cup B)=P(R)+P(B)-P(R\cap B)\\\\P(R\cup B)=0.60+0.70-0.42\\\\P(R\cup B)=0.88\\\\P(R\cup B)=88\%$

Hence, there are 88% chances that one or the other but not both of the units will be successful.

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