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NeX [460]
4 years ago
10

Identify the vertex and the y intercept of the graph of function y=24(x+5.5)^2

Mathematics
2 answers:
JulijaS [17]4 years ago
7 0

Answer:

It's B the second one

Step-by-step explanation:

Mila [183]4 years ago
5 0
Vertex: (-5.5, 0)

The Y-Intercept is: (0, 726)
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Simplify using order of operations 12-36 divided by 9
tiny-mole [99]

Answer:

8

Step-by-step explanation:

36/9=4

12-4=8

8 is your answer

8 0
3 years ago
Can I get help with finding the Fourier cosine series of F(x) = x - x^2
trapecia [35]
Assuming you want the cosine series expansion over an arbitrary symmetric interval [-L,L], L\neq0, the cosine series is given by

f_C(x)=\dfrac{a_0}2+\displaystyle\sum_{n\ge1}a_n\cos nx

You have

a_0=\displaystyle\frac1L\int_{-L}^Lf(x)\,\mathrm dx
a_0=\dfrac1L\left(\dfrac{x^2}2-\dfrac{x^3}3\right)\bigg|_{x=-L}^{x=L}
a_0=\dfrac1L\left(\left(\dfrac{L^2}2-\dfrac{L^3}3\right)-\left(\dfrac{(-L)^2}2-\dfrac{(-L)^3}3\right)\right)
a_0=-\dfrac{2L^2}3

a_n=\displaystyle\frac1L\int_{-L}^Lf(x)\cos nx\,\mathrm dx

Two successive rounds of integration by parts (I leave the details to you) gives an antiderivative of

\displaystyle\int(x-x^2)\cos nx\,\mathrm dx=\frac{(1-2x)\cos nx}{n^2}-\dfrac{(2+n^2x-n^2x^2)\sin nx}{n^3}

and so

a_n=-\dfrac{4L\cos nL}{n^2}+\dfrac{(4-2n^2L^2)\sin nL}{n^3}

So the cosine series for f(x) periodic over an interval [-L,L] is

f_C(x)=-\dfrac{L^2}3+\displaystyle\sum_{n\ge1}\left(-\dfrac{4L\cos nL}{n^2L}+\dfrac{(4-2n^2L^2)\sin nL}{n^3L}\right)\cos nx
4 0
3 years ago
What is |3| - 7...............
Ad libitum [116K]
The absolute value of 3 =3
So 3-7= -4
6 0
3 years ago
Man has $100 and wants to buy a radio and earphones. All radios and earphones are 25% off the List price and NO sales tax.
-Dominant- [34]
To find what 25 percent of 130 is we must convert 25 to a decimal. 0.25
Then we multiply .25 and 130 to get 32.5 dollars off 130. This means that the radio and earphones will cost $97.50 and you will have $2.50 remaining. 
If this helped you out Brainliest answer would be appreciated
5 0
3 years ago
Read 2 more answers
Identify the terms and like terms in the expression 14 – 8x– 6 - 10x.
grin007 [14]

Answer:

Like terms are similar and terms are different.

Like terms :-

  • -10
  • 14
  • -6

They are similar.

Terms :-

  • -8x²
  • -10x

One has an exponent and other does not which means they are not like terms and are only terms.

Hope this helps, thank you :) !!

4 0
3 years ago
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