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jeka57 [31]
4 years ago
11

For the graphed function f(x) = (2)^x + 2 + 1, calculate the average rate of change from x = -2 to x = 0

Mathematics
1 answer:
Monica [59]4 years ago
5 0
X1=-2 and x2=0
We need to find y1 and y2 so
F(-2)=2^(-2+2)+1=2
The point(x1,y1)=(-2,2)
F(0)=2^(0+2)+1=5
The point(x2,y2)=(0,5)
Now, calculate the average rate of change (slope):
m = (y2 – y1) / (x2 – x1) =(5-2)/(0-(-2))
m=3/2
The answer is c
Hope it helps
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Find a counterexample to show that the statement is false. Assume all sets are subsets of a universal set U = {1, 2, 3, 4, 5}. (
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Answer:

For subsets A={1,2},B={2,3},C={1,2 5} of U = {1, 2, 3, 4, 5}.

A ∪ (B − C) = (A ∪ B) − (A ∪ C) does not hold.

Step-By-Step Explanation:

U = {1, 2, 3, 4, 5}.

A={1,2}

B={2,3}

C={1,2 5}

For the Left Hand Side

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A ∪ (B − C)= {1,2} ∪ {3} ={1,2,3}

Likewise, the Right Hand Side:

(A ∪ B)={1,2,3}

(A ∪ C)={1,2,5}

(A ∪ B)- (A ∪ C)= {1,2,3}-{1,2,5}={3}

Since, {1,2,3} ≠ {3}, A ∪ (B − C) = (A ∪ B) − (A ∪ C) does not hold.

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3 years ago
Eliminate the parameter t to find a cartesian equation for x=t^2 y=2+10t
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Hello :
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3 0
3 years ago
. An individual wishes to invest $5000 over the next year in two types of investment: Investment A yields 5%, and investment B y
tresset_1 [31]

Answer:

The amount invested at Investment A must be greater than or equal to $2,750

The amount invested at Investment B must be less than or equal to $2,250

Step-by-step explanation:

Let

x -----> the amount invested at Investment A yields 5%

y -----> the amount invested at Investment B yields 8%

we know that

x+y=5,000

x=5,000-y  -----> equation A

x \geq 0.25(5,000)

x \geq \$1,250 -----> inequality B

y \leq 0.50(5,000)

y \leq \$2,250 -----> inequality C

x \geq \frac{1}{2}y -----> inequality D

Substitute equation A in the inequality D and solve for y

5,000-y \geq \frac{1}{2}y

Multiply by 2 both sides

10,000-2y \geq y

Multiply by -1 both sides

-10,000+2y \leq -y

Adds y both sides

-10,000+2y+y \leq 0

-10,000+3y \leq 0

adds 10,000 both sides

3y \leq 10,000

Divide by 3 both sides

y \leq \$3,333.33 -----> inequality E

therefore

<em>Solve for y</em>

we have

y \leq \$2,250 -----> inequality C

y \leq \$3,333.33 -----> inequality E

The solution of inequality C and inequality E is

y \leq \$2,250

For y=2,250

x=5,000-y ----> x=5,000-2,250=2,750

so

x \geq \$2,750 -----> inequality F

<em>Solve for x</em>

we have

x \geq \$1,250 -----> inequality B

x \geq \$2,750 -----> inequality F

The solution of inequality B and inequality F is

x \geq \$2,750

therefore

The amount invested at Investment A must be greater than or equal to $2,750

The amount invested at Investment B must be less than or equal to $2,250

7 0
3 years ago
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