We can use the formula for a parabola:
where
is the origin of the parabola and
is some constant scaling factor.
We are given that the center of the arch on the bridge is
. This is our origin. So our equation is:
Now we just need to find c. We can do this by plugging in one of the other points given:
So our final equation for the arch of the bridge is:
I don’t know what some of that means but I can do the start for you? You rearrange
2x-y=1.
To do this, you +y to both sides, giving you 2x=1+y and then you minus 1, giving you 2x-1=y
Which can be rewritten the other way round to make it slightly easier
y=2x-1
You also have y=5x-5
These are both straight line equations and are now in the form y=mx+c
To sketch these graphs I would do two tables.
X -3 -2 -1 0 1 2 3
Y
For this, you now substitute each of the values for X into one of the equations you have. This is 2x-y=1 (2x-1=y)
X -3 -2 -1 0 1 2 3
Y -7 -5 -3 -1 1 3 5
You may have noticed a pattern there, the y values increased by two each time. This makes it linear. You would plot that line, onto an axis, using the coordinates you now have.
So, (-3, -7), (-2,-5), (-1,-3), (0,-1), (1,1), (2,3), (3,5)
Then I would do the same for the second equation, and plot that too.
X -3 -2 -1 0 1 2 3
Y -20 -15 -10 -5 0 5 10
You may have spotted this time the values increased by 5.
Then again plot this line using the coordinates shown.
I honestly have no idea what it means by “the line system on a corporate” but if that means on an axis then there’s your answer. If not then I do not know.
Hope this helps?
Answer:
a) 0.125
b) 7
c) 0.875 hr
d) 1 hr
e) 0.875
Step-by-step explanation:l
Given:
Arrival rate, λ = 7
Service rate, μ = 8
a) probability that no requests for assistance are in the system (system is idle).
Let's first find p.
a) ρ = λ/μ
Probability that the system is idle =
1 - p
= 1 - 0.875
=0.125
probability that no requests for assistance are in the system is 0.125
b) average number of requests that will be waiting for service will be given as:
λ/(μ - λ)
= 7
(c) Average time in minutes before service
= λ/[μ(μ - λ)]
= 0.875 hour
(d) average time at the reference desk in minutes.
Average time in the system js given as: 1/(μ - λ)
= 1 hour
(e) Probability that a new arrival has to wait for service will be:
λ/μ =
= 0.875
