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3 years ago

What is 55% of 80 Answer: 8, 80,4.4 or 44

2 answers:

7 0

We convert 55% to either a fraction or decimal:

55%= $\frac{55}{100}$ = 0.55

We multiply the given by the percentage if the question asks for the percentage of a numeral.

80 × 0.55 = 44
The answer is 44

vova2212 [387]3 years ago

3 0

44. you multiply 80 by .55

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40% of collage students scored more than 70% on a math test. 120 students scored below that. How many total students took the ma

monitta

The answer to your question is 200.
100%-40%=60%
60%=120 students
60%÷3=20%
120÷3=40
20%=40
20%X5=100%
40X5=200

3 0

3 years ago

Assume the total cost of a college education will be $235,000 when your child enters college in 18 years. You presently have $53

Andrei [34K]

Answer:

Step-by-step explanation:

We would apply the formula for determining compound interest which is expressed as

A = P(1+r/n)^nt

Where

A = total amount in the account at the end of t years

r represents the interest rate.

n represents the periodic interval at which it was compounded.

P represents the principal or initial amount deposited

From the information given,

A = $235,000

P = $53,000

n = 1 because it was compounded once in a year.

t = 18 years

Therefore,.

235000 = 53000(1 + r/1)^1 × 18

235000/53000 = (1 + r)^18

4.43 = (1 + r)^18

Raising both sides to the power of 1/18, it becomes

4.43^(1/18) = (1 + r)^18 × 1/18

1.086 = 1 + r

r = 1.086 - 1

r = 0.086

r = 0.086 × 100 = 8.6%

6 0

3 years ago

Find the variable x the diagram is not drawn to scale if you could explain it would also help

Vlad1618 [11]

Answer:

Step-by- its ab s

7 0

3 years ago

Find the deriative dy/dx for y=x^2-2x/x^3+3

vaieri [72.5K]

Answer:

$\frac{dy}{dx}=(\frac{(2x-2)(x^3+3)-(x^2-2x)(3x^2)}{(x^3+3)^2})$

Step-by-step explanation:

So we want to find the derivative of the rational equation:

$y=\frac{x^2-2x}{x^3+3}$

First, recall the quotient rule:

$(\frac{f}{g})'=\frac{f'g-fg'}{g^2}$

Let f be x^2-2x and let g be x^3+3.

Calculate the derivatives of each:

$f=x^2-2x\\f'=2x-2$

$g=x^3+3\\g=3x^2$

So:

$\frac{dy}{dx}=(\frac{x^2-2x}{x^3+3})'$

Use the above format:

$\frac{dy}{dx}=\frac{f'g-fg'}{g^2}\\\frac{dy}{dx}=(\frac{(2x-2)(x^3+3)-(x^2-2x)(3x^2)}{(x^3+3)^2})$

And that's our answer :)

(If you want to, you can also expand. However, no terms will be canceled.)

8 0

3 years ago

A periscope is 5 feet above the surface of the ocean. Through it can be seen a ship that rises to 50 feet above the water. To th

Lyrx [107]

Sketch this, assuming the Earth is a sphere with radius R, so a plane slice through the periscope, ship and center of the Earth is a circle of radius R. Draw the lines out from the center (O) of the circle to point A at the top of the periscope and point B at the top of the ship. so that line AB is tangent to the circle at point C. That makes triangles OAC and OBC right triangles, each having the right angle at C. 

From the problem, the lengths OA = R+5, OC = R, and OB=R+50. Label the lengths AC = p and BC= q, then use Pythagoras: 

R² + p² = (R + 5)² 
R² + q² = (R + 50)² 

Solve those: 
p² = (R + 5)² - R² = 10R - 25 
p = √(10R + 25) 

q² = (R + 50)² - R² = 100R + 2500 
q = √(100R + 2500) 

Find a good value for the radius R (in ft. units!) and calculate. The distance from periscope top to ship top is (p + q) feet. Convert that to miles for your answer.

8 0

4 years ago