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3 years ago

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(4 points) The cost of a parking ticket is $30 for the first offense, but the cost doubles for each additional offense. Write a

formula for
the cost C(n) as a function of the number of tickets n.
Problems
find C(n)=

1 answer:

lisabon 2012 [21]3 years ago

4 0

Answer

30+ n^2= c

Step-by-step explanation:

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PLEASE HELP I’LL GIVE BRAINLIST.

kolezko [41]

Answer:

2/6 is probably your answer

Step-by-step explanation:

5 0

3 years ago

LCM of 14 and 49? Evaluate plz

ICE Princess25 [194]

Answer:

98

Step-by-step explanation:

Express the numbers in terms of the product of their prime factors

14 = 2 × 7

49 = 7 × 7 = 7²

Choose the factors which occur most often between the 2 numbers

LCM = 2 × 7² = 2 × 49 = 98

5 0

3 years ago

People in Spaceland live in 8 space stations, and travel between the stations in tubes.Every pair of stations is connected by tw

NeTakaya

Based on the way these stations are connected, we can infer that there are <u>56 tubes. </u>

<h3>Number of tubes in Spaceland </h3>

Each pair of stations have 2 tubes. This means that every station is connected to each of the others.

We can therefore infer that each station has 7 tubes to the other stations.

The total number of tubes would therefore be:

= Number of stations x Number of tubes per station

= 8 x 7

= 56 tubes

In conclusion, there are 56 tubes.

Find out more on proportionality problems at brainly.com/question/24822176.

3 0

2 years ago

Read 2 more answers

Explain how to get that answer!!

ra1l [238]

We need to simplify $\frac{ \sqrt{14x^3} }{ \sqrt{18x} }$

First lets factor $\sqrt{14x^3}$

$\sqrt{14x^3}$ = $\sqrt{14} \sqrt{x^3}$
$\sqrt{14} = \sqrt{2} \sqrt{7}$ by applying the radical rule $\sqrt[n]{ab} = \sqrt[n]{a} \sqrt[n]{b}$
$\sqrt{x^3} = x^{3/2}$ By applying the radical rule $\sqrt[n]{x^m} = x^{m/n}$

So
$\sqrt{14x^3}$ = $\sqrt{14} \sqrt{x^3}$ = $\sqrt{2} \sqrt{7}x^{3/2}$

Now let's factor $\sqrt{18x}$
By applying the radical rule $\sqrt[n]{ab} = \sqrt[n]{a} \sqrt[n]{b}$ ,
$\sqrt{18x} = \sqrt{18} \sqrt{x}$
$\sqrt{18} = \sqrt{2} * 3$

So $\sqrt{18x}$ = $\sqrt{2}*3 \sqrt{x}$

So $\frac{ \sqrt{14x^3} }{ \sqrt{18x} }$ = $\frac{ \sqrt{2} \sqrt{7} x^{3/2} }{ \sqrt{2}*3 \sqrt{x} }$

We know that $\sqrt[n]{x} = x^{1/n}$ so $\sqrt{x} = x^{1/2}$

We now have $\frac{ \sqrt{2} \sqrt{7} x^{3/2} }{ \sqrt{2}*3 \sqrt{x}} = \frac{ \sqrt{2} \sqrt{7} x^{3/2} }{ \sqrt{2}*3x^{1/2}}$

We know that $\frac{x^a}{x^b} = x^{a-b}$
So $\frac{x^{3/2}}{x^{1/2}} = x^{3/2 - 1/2} = x$

We now got $\frac{ \sqrt{2} \sqrt{7} x^{3/2} }{ \sqrt{2}*3x^{1/2}} = \frac{ \sqrt{2} \sqrt{7} x }{ \sqrt{2}*3}
$

We can notice that the numerator and the denominator both got √2 in a multiplication, so we can simplify them, and we get:
$\frac{ \sqrt{2} \sqrt{7} x }{ \sqrt{2}*3} = \frac{ \sqrt{7}x }{3}$

All in All, we get $\frac{ \sqrt{14x^3} }{ \sqrt{18x} }$ = $\frac{ \sqrt{7}x }{3}$

Hope this helps! :D

6 0

3 years ago

On monday there were 92 fish in the fish tank on tuesday 4 fish were sold on wednesday 1 fish was sold on thursday 4fish were ad

Julli [10]

Monday=92
Tuesday=88
Wednesday=87
Thursday=91
Friday=88
There are 88 fish remaining

7 0

3 years ago