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3 years ago

Help pleaseeeeeeeeee

Mathematics

1 answer:

Viktor [21]3 years ago

6 0

Answer: Area of Δ DUO = 12.0 square units.

Step-by-step explanation:

From the diagram, Δ DPA is a right angled triangle and right angled at P.

Therefore ∠D will be

Tan ∅° = PA/DP ie, opposite side all over the adjacent.

= 4.5/3.75

Tan∅° = 1.2

to calculate ∅°, we know find the inverse of Tan 1.2

∅ = Tan^-1 1 .2 from your log tables or calculator

∅° = 50.20°.

= 50°

Since line DR is ⊥ to line OP

∠ADR = 90° - 50°

= 40°.

From the diagram,

∠ADR = ∠UDR = 40°

Therefore,

∠ODU = 180 - ( 40 + 40 + 90 ) { Angle on a straight line }

= 180 - 170

= 10°

From Δ UDM , line MU is he height of the required Δ DUO whose area is to be determined.

Now find the height MU

Tan10.0° = MU/10, where MU is the opposite side and 10.0 is the adjacent from the diagram given.

MU = Tan10.0 x 10.0

= 0.1763 x 10.0

= 1.763

Therefore to calculate the area of Δ DUO

= 1/2 x base x height

= 1/2 x line OD x line MU

= 1/2 x 14.0 x 1.763

= 7 x 1.763

= 12.341

= 12.0 square units.

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Help pleaseeeeeeeeee​

Help pleaseeeeeeeeee