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4 years ago

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suppose you observed the size of the deer population in an area. you discovered that over a 3 year period, the population change

d in the following way: 40 deer were born, 18 deer died, 20 deer migrated into the herd, and 6 deer migrated out of it. calculate the growth rate, per year, of the population. be sure to consider changes brought about by immigration and emigration. show your work

1 answer:

Eduardwww [97]4 years ago

3 0

12 population growth per year. 40-18+20-6=36
36÷3=12

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A) In the Dunker population, the frequency of IB allele is 0.3 and the frequency of i allele is 0.4. In the general population, the frequency of IB allele is 0.1 and t<span>he frequency of i allele is 0.5.
</span>
If:
$I^{A}$ - <span>the frequency of IA allele
</span> $I^{B}$ - <span>the frequency of IB allele
</span> $i$ - t<span>he frequency of i allele

Then:
</span> $I^{A} I^{A}$ + <span> $I^{A} i$ - the frequency of individuals with A blood type
</span> $I^{B} I^{B}$ + <span> $I^{B} i$ - the frequency of individuals with B blood type
</span> $ii$ <span>- the frequency of individuals with O blood type
</span>
Let's first take a look on the Dunker population:
$I^{A} = 0.3$
$ii=0.16
$

<span>Since there is only one possible genotype for O individuals - ii - the frequency of the allele i is square root of the frequency of O individuals:
</span> $i= \sqrt{ii}$
⇒ $i = \sqrt{0.16}$
⇒ $i=0.4$

Now, we have the frequencies of two alleles ( $I^{A}$ and $i$ ). To calculate the frequency of $I^{B}$ <span> allele, we will use the formula:
</span> $I^{A} + I^{B} + i = 1$
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$I^{A} = 0.4$
$ii=0.25$

<span>Similarly to the work for the Dunker population:
</span> $i= \sqrt{ii}$
⇒ $i = \sqrt{0.25}$
⇒ $i=0.5$

$I^{A} + I^{B} + i = 1$
⇒ $I^{B} = 1- I^{A} - i$
⇒ $I^{B} = 1-0.4-0.5$
<span>⇒ $I^{B} = 0.1$
</span>

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