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Oksi-84 [34.3K]
3 years ago
8

PLEASE HELP?

Mathematics
1 answer:
Darya [45]3 years ago
8 0

Answer:

1/3

Step-by-step explanation:

The number of people over 40 is 20 + 30 + 35 = 85.

So the probability is 85/255, which reduces to 1/3.

You might be interested in
Carpet for one office costs $210. If the carpet sells for $8.75 per
Ilia_Sergeevich [38]

Answer:

a.

Let x be the number of square yards of carpeting for which the total cost charged by the two companies will be the same.

We have an expression for the total cost of Country Carpets:

($22/ 1 yd^2)* (x yd^2) + $100

= $22*x+ $100

or 22x+ 100

We also have another expression for the total cost of City Carpets:

($25/ 1 yd^2)* (x yd^2)+ $70

= $25*x+ $70

or 25x+ 70

Now set the two expressions to be equal:

22x+ 100= 25x+ 70

⇒ 100- 70= 25x -22x

⇒ 30= 3x

⇒ 30/3= x

⇒ 10= x

The final answer for a is 10 square yards of carpeting~

b.

Let's assume that Mr. Shu wants to install carpeting for 1 square yard.

Country Carpets: $22*1+ $100= $122

City Carpets: $25*1+ $70= $95

Therefore, Mr. Shu will be likely to choose City Carpets if he wants to install carpeting for 1 square yard.

Now let's try x=11 (square yard):

Country Carpets= $22*11+ $100= $342

City Carpets= $25*11+ $70= $345

Therefore, Mr. Shu will be likely to choose Country Carpets if he wants to install carpeting for 11 square yard.

If you paid really close attention, you would notice that the price of City Carpets will be cheaper than the other when x is >0 and <10. At x=10, the price is equal. When x is >10, the price of Country Carpets will be cheaper than the other one.

So it depends:

If x were >0 and <10, Mr. Shu would be likely to choose City Carpets.

If x were 10, Mr. Shu could choose either Country Carpets or City Carpets.

If x were > 10, Mr. Shu would be likely to choose Country Carpets.

Hope this helps~

Step-by-step explanation:

7 0
2 years ago
Place
Anastaziya [24]

Answer:

P(A\ and\ B) = \frac{3}{7}

Step-by-step explanation:

<em>Your question is not well presented; (See Attachment for complete details)</em>

<em></em>

Required

Find P(A n B)

where

A = Event that the place is a city

B = Event that the place is in North

The first step is to get the sample space;

Let S represent the sample space;

S = \{India,\ Tokyo,\ Houston,\ Peru,\ New York,\ Tijuana,\ Canada \}

n(S) = 7

The next is to list events A and B

A = City

A = \{Tokyo,\ Houston,\ New York,\ Tijuana\}

B = North America

B = \{Houston,\ New York,\ Tijuana,\ Canada\}

The next is to list common elements in A and B

A\ n\ B = \{Houston,\ New York,\ Tijuana\}

n(A\ and\ B) = 3

The probability of A and B is calculated as follows;

P(A\ and\ B) = \frac{n(A\ and\ B)}{n(S)}

Substitute n(A\ and\ B) = 3 and n(S) = 7 in the expression above

P(A\ and\ B) = \frac{3}{7}

7 0
3 years ago
Need help with the last 2 numbers ​
professor190 [17]

Answer:

the solution is t ≤1 (1)

6 0
2 years ago
How would you solve this problem 999 + 587 = 1000 + what = what ? How would this problem be solved
bija089 [108]

Answer:

2,586

Step-by-step explanation:

Add 1000+1000

2000

Since its 999 not 1000 subtract 1

1999

Now add 1 and subtract 1 from 587

Then add 2000 with 586

2,586

3 0
3 years ago
Read 2 more answers
In Triangle XYZ, measure of angle X = 49° , XY = 18°, and
marissa [1.9K]

Answer:

There are two choices for angle Y: Y \approx 54.987^{\circ} for XZ \approx 15.193, Y \approx 27.008^{\circ} for XZ \approx 8.424.

Step-by-step explanation:

There are mistakes in the statement, correct form is now described:

<em>In triangle XYZ, measure of angle X = 49°, XY = 18 and YZ = 14. Find the measure of angle Y:</em>

The line segment XY is opposite to angle Z and the line segment YZ is opposite to angle X. We can determine the length of the line segment XZ by the Law of Cosine:

YZ^{2} = XZ^{2} + XY^{2} -2\cdot XY\cdot XZ \cdot \cos X (1)

If we know that X = 49^{\circ}, XY = 18 and YZ = 14, then we have the following second order polynomial:

14^{2} = XZ^{2} + 18^{2} - 2\cdot (18)\cdot XZ\cdot \cos 49^{\circ}

XZ^{2}-23.618\cdot XZ +128 = 0 (2)

By the Quadratic Formula we have the following result:

XZ \approx 15.193\,\lor\,XZ \approx 8.424

There are two possible triangles, we can determine the value of angle Y for each by the Law of Cosine again:

XZ^{2} = XY^{2} + YZ^{2} - 2\cdot XY \cdot YZ \cdot \cos Y

\cos Y = \frac{XY^{2}+YZ^{2}-XZ^{2}}{2\cdot XY\cdot YZ}

Y = \cos ^{-1}\left(\frac{XY^{2}+YZ^{2}-XZ^{2}}{2\cdot XY\cdot YZ} \right)

1) XZ \approx 15.193

Y = \cos^{-1}\left[\frac{18^{2}+14^{2}-15.193^{2}}{2\cdot (18)\cdot (14)} \right]

Y \approx 54.987^{\circ}

2) XZ \approx 8.424

Y = \cos^{-1}\left[\frac{18^{2}+14^{2}-8.424^{2}}{2\cdot (18)\cdot (14)} \right]

Y \approx 27.008^{\circ}

There are two choices for angle Y: Y \approx 54.987^{\circ} for XZ \approx 15.193, Y \approx 27.008^{\circ} for XZ \approx 8.424.

6 0
3 years ago
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