3.The snow starts at a depth of 10 inches and melts to 2 inches over the span of 4 hours. Determine the rate of change over the
1 answer:
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Answer:
The period of the function is
. Then three times this period is
.
Step-by-step explanation:
Using Mathematica you can use the command Plot as follows:
```
Plot[Sin[x], {x,0,6Pi}]
```
The output is the graph shown below.
N = number of compounding periods
Years = log (total / principal) / n * log (1 + rate / n)
Years = log (750 / 500) / 4 * log (1 + .025/n)
Years = log (1.5) / 4 * log (1<span><span>.00625) </span>
</span> <span>Years = 0.17609125906 / 4 * 0.0027058933759
</span><span>Years = 0.17609125906 </span> / <span> <span> <span> 0.0108235735 </span> </span> </span>
Years = <span> <span> <span> 16.2692348382 </span> </span> </span>
Source Calculator
http://www.1728.org/compint.htm
Years = log (total / principal) / n * log (1 + rate / n)
Years = log (750 / 500) / 4 * log (1 + .025/n)
Years = log (1.5) / 4 * log (1<span><span>.00625) </span>
</span> <span>Years = 0.17609125906 / 4 * 0.0027058933759
</span><span>Years = 0.17609125906 </span> / <span> <span> <span> 0.0108235735 </span> </span> </span>
Years = <span> <span> <span> 16.2692348382 </span> </span> </span>
Source Calculator
http://www.1728.org/compint.htm
Answer:
Step-by-step explanation:
Since, angle 1 is an exterior angle of ΔABE,
m∠1 > m∠3 and m∠4
Since, angle 1 is an exterior angle of ΔABD,
m∠1 > m∠5
Since, angle 1 is an exterior angle of ΔABC,
m∠1 > m∠7 and m∠8
Therefore, ∠1 is greater than ∠3, ∠5, ∠7 and ∠8.
