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3 years ago

Write the standard form of the line that contains a slope of and y-intercept of 3. Include your work in your final answer.

Mathematics

1 answer:

Brut [27]3 years ago

7 0

Standard form is y=mx+b, where m is the slope and b is the y intercept, substitute to find y=3x+3.
Hope this helps!

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4(x+8)-2(x-7)=46 x=?

Scorpion4ik [409]

Answer:

x = 0/2

x = 0

Step-by-step explanation:

4(x+8)-2(x-7) = 46

Expanding the brackets

4x +32 - 2x +14 = 46

2x + 46 = 46

2x = 46-46

2x = 0

x = 0/2

x = 0

5 0

3 years ago

A town's total allocation for firefighter's wages and beneﬁts in a new budget is $600,000. If wages are calculated at $40,000 pe

tiny-mole [99]

There is 8 firefighters

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3 years ago

-9(m+3) +14=-49 please show work

yKpoI14uk [10]

Answer:

m=4

Step-by-step explanation:

−9(m+3)+14=−49

Step 1: Simplify both sides of the equation.

−9(m+3)+14=−49

(−9)(m)+(−9)(3)+14=−49(Distribute)

−9m+−27+14=−49

(−9m)+(−27+14)=−49(Combine Like Terms)

−9m+−13=−49

−9m−13=−49

Step 2: Add 13 to both sides.

−9m−13+13=−49+13

−9m=−36

Step 3: Divide both sides by -9.

−9m

−9

−36

−9

m=4

8 0

3 years ago

The 2 in the middle is the one that I needed help <br> Please

r-ruslan [8.4K]

Answer:

The equation is p=34a+12, and a=7

Step-by-step explanation:

Perimeter is all of the sides added together

p=12a+6a+8+6a+8+10a-4

Combine like-terms

p=34a+12

Solve for a by making p equal to 250

250=34a+12

Subtract 12 from both sides

238=34a

Divide both sides by 34

7=a

4 0

3 years ago

When the sum of \, 528 \, and three times a positive number is subtracted from the square of the number, the result is \, 120. F

aleksandr82 [10.1K]

Let $x$ be the unknown number. So, three times that number means $3x$ , and the square of the number is $x^2$

We have to sum 528 and three times the number, so we have $528+3x$

Then, we have to subtract this number from $x^2$ , so we have

$x^2-(3x+528)$

The result is 120, so the equation is

$x^2 - 3x - 528 = 120 \iff x^2 - 3x - 648 = 0$

This is a quadratic equation, i.e. an equation like $ax^2+bx+c=0$ . These equation can be solved - assuming they have a solution - with the following formula

$x_{1,2} = \dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$

If you plug the values from your equation, you have

$x_{1,2} = \dfrac{3\pm\sqrt{9-4\cdot(-648)}}{2} = \dfrac{3\pm\sqrt{9+2592}}{2} = \dfrac{3\pm\sqrt{2601}}{2} = \dfrac{3\pm51}{2}$

So, the two solutions would be

$x = \dfrac{3+51}{2} = \dfrac{54}{2} = 27$

$x = \dfrac{3-51}{2} = \dfrac{-48}{2} = -24$

But we know that x is positive, so we only accept the solution $x = 27$

6 0

3 years ago