Ask question

Ask question

All categories

3 years ago

6

Escribe dos fracciones equivalentes de 12 20

1 answer:

Shalnov [3]3 years ago

3 0

24/40 multiplicado por 2 y 6/10 dividiendo entre 2 las dos son equivalentes

You might be interested in

Do Number 20 Please

Luda [366]

2 3/20 ,2 9/20, 2 1/2,2 11/20,2 4/5

5 0

2 years ago

What means lateral in math

Len [333]

Lateral surface area is the sum of all sides of a 3D object EXCEPT it's top and bottom bases.

7 0

3 years ago

How the transformations of the functions f(x)=15tanx and g(x)=tanx+15 differ?

Irina-Kira [14]

The transformation of <span>f(x)=15tanx would be achieved by dilating y</span>=tanx graph 15 times. This transformation will cause y'=15 y. This will increase the value of dilation become 15 times of the original

The transformation of g(x)=15tanx would be achieved by shifting y=tanx graph 15 right. This transformation will cause x'=x+15. This will change the value from tan x into tan(x+15)

3 0

3 years ago

Read 2 more answers

Pat was in a fishing competition at

aliina [53]

Let me know if you can see the pictures well

6 0

2 years ago

Which could be the first step in simplifying this expression? Check all that apply. (x cubed x Superscript negative 6 Baseline)

PtichkaEL [24]

Answer:

$(x^{-3} )^{2}$

$x^6 x^{-12}$

Step-by-step explanation:

$(x^{3} x^{-6} )^{2}$ is the expression given to be solved.

First of all let us have a look at <u>3 formulas</u>:

$1.\ p^a \times p^b = p^{(a+b)}\\2.\ (p^a \times q^b)^c = (p^{a})^c \times (q^{b})^c\\3.\ (p^a)^b = p^{a\times b}$

Both the formula can be applied to the expression( $(x^{3} x^{-6} )^{2}$ ) during the first step while solving it.

<u>Applying formula (1):</u>

$(x^{3} x^{-6} )^{2}$

Comparing the terms of $(x^{3} x^{-6} )$ with $p^a \times p^b$

$p=x, a =3, b=-6$

$\Rightarrow x^{3+(-6)}\\\Rightarrow x^{3-6}\\\Rightarrow x^{-3}$

So, $(x^{3} x^{-6} )^{2}$ is reduced to $(x^{-3} )^{2}$

<u>Applying formula (2):</u>

Comparing the terms of $(x^{3} x^{-6} )^{2}$ with $(p^a \times q^b)^c$

$p=q=x, a =3, b=-6, c=2$

$\Rightarrow (x^{3})^2\times (x^{-6})^2\\\text{Applying Formula (3)}\\x^6 x^{-12}$

So, $(x^{3} x^{-6} )^{2}$ is reduced to $x^6 x^{-12}$ .

So, the answers can be:

$(x^{-3} )^{2}$

$x^6 x^{-12}$

8 0

2 years ago