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Zina [86]
3 years ago
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How many times longer is the wavelength of a sound wave with a frequency of 20 waves per second than the wavelength of a sound w
sergejj [24]

The sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec

<h3>Calculating wavelength </h3>

From the question, we are to determine how many times longer is the first sound wave compared to the second sound water

Using the formula,

v = fλ

∴ λ = v/f

Where v is the velocity

f is the frequency

and λ is the wavelength

For the first wave

f = 20 waves/sec

Then,

λ₁ = v/20

For the second wave

f = 16,000 waves/sec

λ₂ = v/16000

Then,

The factor by which the first sound wave is longer than the second sound wave is

λ₁/ λ₂ = (v/20) ÷( v/16000)

= (v/20) × 16000/v)

= 16000/20

= 800

Hence, the sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec

Learn more on Calculating wavelength here: brainly.com/question/16396485

#SPJ1

6 0
2 years ago
What is the solution for the system<br> of equations shown IN the graph?
noname [10]

Answer:

(2,4)

Step-by-step explanation:

The solution for the system is where the two lines intersect.

The two lines intersect at x = 2 and y =4

(2,4)

5 0
2 years ago
Read 2 more answers
What is the distance between A(0, 5) and B(5, -7) ?
lord [1]

Answer:

The distance between the two points is 13 units.

Step-by-step explanation:

take the test

4 0
3 years ago
Help me please and thank you
sdas [7]

Answer:

Based on the model, the length of the wall is \frac{9}{8} ft, the width of the wall is \frac{1}{2} ft,  and the height of the wall is \frac{11}{8} ft. The volume of the portion of security wall that  Tim has constructed so far is \frac{99}{128}  cu ft.

Step-by-step explanation:

Given:

The figure constructed shows a rectangular prism made up of small wooden cubes of length \frac{1}{8}\ ft.

Width of the prism = \frac{1}{2}\ ft.

To find length , height and volume of the figure.

Solution:

From the figure we can conclude that :

Length side of the prism counts 9 cubes.

Thus, length of the prism will be given as :

⇒ \textrm{Length of each cube}\times \textrm{Number of cubes}

⇒ \frac{1}{8}\ ft\times 9

⇒ \frac{9}{8}\ ft  (Answer)

Height side of the prism counts 11 cubes.

Thus, height of the prism will be given as :

⇒ \textrm{Length of each cube}\times \textrm{Number of cubes}

⇒ \frac{1}{8}\ ft\times 11

⇒ \frac{11}{8}\ ft (Answer)

Volume of the prism can be given as :

⇒ Length\times width\times height

⇒ \frac{9}{8}\ ft\times \frac{1}{2}\ ft\times \frac{11}{8}\ ft

⇒ \frac{99}{128}\ ft^3 (Answer)

7 0
3 years ago
What is the x-intercept of the equation 3x - 2y = -12 ​
muminat
X=2/3y-4

EXPLANATION
3x-2y=-12
You take -2y to the other side
It becomes 3x=2y-12
Then you divide 3
X=2/3y
-12/3=-4
X=2/3y-4
4 0
3 years ago
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