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Find the area of the following

kozerog [31]

Answer:

Area = 12

Step-by-step explanation:

The perpendicular bisector of the triangle going from upper left to the middle marks the height of the triangle. It's area is found from the standard formula.

Area = b * h / 2

b = 2 + 2 = 4

h = 8

Area = 1/2 * 4 * 8

Area = 1/2 * 32

Area = 16

The smaller triangle is found from all the twos.

b = 2 + 2 same as the larger triangle

h = 2

Area = 1/2 2 * 4

Area = 1/2 8

Area = 4

Total Area = 4 + 16

Total Area = 20

7 0

3 years ago

3. The length of a living room is 12 feet and its width is 10.5 feet. The length of the room is being

Liono4ka [1.6K]

Since you're adding x feet to the length which is 12 feet:

New area: (12+x)10.5

5 0

3 years ago

The perimeter of the triangular park on the right is 16x-6. What is the missing length? The bottom side length is 5x+4 and the r

Romashka-Z-Leto [24]

Answer:

$(9x-5)\ units$

Step-by-step explanation:

<u><em>The picture of the question in the attached figure</em></u>

we know that

The perimeter of a triangle is the sum of the length of their three sides

$P=a+b+c$

where

a,b,c are the length sides of the triangle

In this problem we have

$P=(16x-6)\ units\\a=(2x-5)\ units\\b=(5x+4)\ units$

substitute and solve for the missing length

$(16x-6)=(2x-5)+(5x+4)+c\\c=(16x-6)-(2x-5)-(5x+4)\\c=(9x-5)\ units$

3 0

3 years ago

What is the area of the sector a.) 10π cm^2b.) 16π cm^2c.) 40π cm^2d.) 64π cm^2

Natalija [7]

Answer:

C. 40π cm²

Explanation:

• The central angle of the sector = 225 degrees

• The radius of the sector = 8cm

For a sector of radius r and central angle θ, we calculate the area using the formula below:

$\text{Area}=\frac{\theta}{360\degree}\times\pi r^2$

Substituting the given values, we have:

$\begin{gathered} \text{Area}=\frac{225}{360}\times\pi\times8^2 \\ =\frac{5}{8}\times64\times\pi \\ =5\times8\times\pi \\ =40\pi cm^2 \end{gathered}$

The area of the sector is 40π cm².

3 0

1 year ago

Sadie simplified the expression √54a^7b^3, where a>=0, as shown: √54a^7b^3= √3^2•6•a^2•a^5•b^2•b=3ab √6a^5b

Tamiku [17]

Answer:

We are to find the error made by Sadie and then find the correct simplification.

The error Sadie made is that she wrote $a^7$ as $a^2 * a^5$ instead of $a^6 * a$ .

The square root of $a^6$ is $a^3$ and so she could have further simplified.

The correct simplification is shown below:

$\sqrt{54a^7b^3} = \sqrt{2 * 3 * 3 * 3 * a^6 * a * b^2 * b} \\ \\= \sqrt{3^2 * a^6 * b^2 * 6 * a * b} \\\\= 3a^3b\sqrt{6ab}$

4 0

3 years ago