Let the given complex number
z = x + ix = 
We have to find the standard form of complex number.
Solution:
∴ x + iy = 
Rationalising numerator part of complex number, we get
x + iy = 
⇒ x + iy = 
Using the algebraic identity:
(a + b)(a - b) =
- 
⇒ x + iy = 
⇒ x + iy =
[ ∵
]
⇒ x + iy =
⇒ x + iy =
⇒ x + iy =
⇒ x + iy = 1 - i
Thus, the given complex number in standard form as "1 - i".
Step-by-step explanation:
▪ x - 3 < 3x - 7
▪ x + 4 < 3x
▪ 4 < 2x
▪ 2 < x
Answer:
2.01
Step-by-step explanation:
If parent functin is f(x)=|x|
it is moved to the left 2 units
vertically streched by a factor of 3
and moved up by 4 units in that order
because
to move a function to left c units, add c to every x
to vertically strech function by factor of c, multiply whole function by c
to move funciotn up c units, add c to whole function
so it is 2 to the left, verteically streched by a factor of 3 then moved up 4 units