<span>negative charge.
The atomic number of 34 tells you immediately that the ion has 34 protons. Since it also has 36 electrons, it has 2 more electrons than needed to be neutral. So the ion will have a negative charge since electrons have a negative charge.</span>
Answer: In a lab guide, the key results are those that support my working hypotheses or serve to reject these assumptions. Moreover, the key results may also be other discoveries that are important to understand the processes and/or mechanisms investigated in the experiment.
1 answer
Explanation:
The sub-atomic particles inside the nucleus of atoms of any element are protons and neutrons. Protons have a positive charge and neutrons are neutral with no charge.
Answer:
40.68 % C
23.73 % N
8.47% H
27.12% O
Explanation:
The mass percent of an element X in a compound is calculated as the molar mass (MM) of X multiplied by the number of atoms of X in the compound, divided into the molecular weight (MW) of the compound, as follows:
mass percent of X = (MM(X) x number of atoms of X)/MW compound x 100
Thus, we first calculate the MW of acetamide (C₂H₅NO) by using the molar mass of the chemical elements C, H, N and O:
MW(C₂H₅NO) = (12 g/mol C x 2) + (1 g/mol H x 5) + 14 g/mol N + 16 g/mol O = 59 g/mol
Now, we can calculate the mass percent of each element (C, H, N, O) in C₂H₅NO:
- Mass percent of C (2 atoms of C in 1 molecule of C₂H₅NO):
% mass C = (12 g/mol x 2)/(59 g/mol) x 100 = 40.68 %
- Mass percent of N (1 atom of N in 1 molecule of C₂H₅NO):
% mass N = (14 g/mol x 1)/(59 g/mol) x 100 = 23.73 %
- Mass percent of H (5 atoms of H in 1 molecule of C₂H₅NO):
% mass H = (1 g/mol x 5)/(59 g/mol) x 100 = 8.47 %
- Mass percent of O (1 atom of O in 1 molecule of C₂H₅NO):
% mass O = (16 g/mol x 1)/(59 g/mol) x 100 = 27.12 %
The sum of the mass percents has to be equal to 100%:
40.68 % C + 23.73 % N + 8.47% H + 27.12% O = 100%
The freezing point of the sucrose solution is -0.435°C.
<h3>What is the freezing point of the solution?</h3>
The freezing point of the solution is determined from the freezing point depression formula below:
Kf(H₂O) = 1.86 Cm
m is molality of solution = moles of solute/mass of solvent
moles of sucrose = 8.0/342.3 = 0.0233 moles
m = 0.0233/0.1 = 0.233 molal
ΔT = 0.233 m * 1.86°C/m.
ΔT = 0.435 °C.
Freezing point of sucrose solution = 0°C - 0.435°C
Freezing point of sucrose solution = -0.435°C.
In conclusion, the freezing point of sucrose solution is determined from the freezing point depression.
Learn more about freezing point depression at: brainly.com/question/19340523
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