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kvv77 [185]
2 years ago
7

What is the molarity of silver ion in the final solution

Chemistry
1 answer:
love history [14]2 years ago
3 0
27.8 mg of silver nitrate (AgNO3, 169.9g/mol) was dissolved in water to make 15.00 mL of solution. 8.15 mL of that solution was diluted to make a new solution with a total volume of 1.000L.
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A solution...
steposvetlana [31]

Answer:

A

Explanation:

8 0
3 years ago
Read 2 more answers
The blank
Alik [6]
I think it’s “number” and “type”
5 0
3 years ago
Answer the following for the reaction: 3AgNO3(aq)+Na3PO4(aq)→Ag3PO4(s)+3NaNO3(aq)
Brums [2.3K]

Answer:1) Volume of AgNO_3 required is 55.98 mL.

2) 0.62577 grams of Ag_3PO_4 is produced.

Explanation:

3AgNO_3(aq)+Na_3PO_4(aq)\rightarrow Ag_3PO_4(s)+3NaNO_3(aq)

1) Molarity of AgNO_3,M_1=0.225 M

Volume of AgNO_3.V_1=?

Molarity of Na_3PO_4,M_2=0.135 M

Volume of Na_3PO_4,V_2=31.1 mL=0.0311 L

Molarity=\frac{\text{number of moles}}{\text{volume of solution in liters}}

\text{number of moles }Na_3PO_4=M_2\times V_2=0.135 mol/L\times 0.0311 L=0.0041985 moles

According to reaction, 1 mole of Na_3PO_4 reacts with 3 mole of AgNO_3, then, 0.0041985 moles of Na_3PO_4 will react with:

\frac{3}{1}\times 0.0041985 moles of AgNO_3 that is 0.0125955 moles.

M_1=0.225 M=\frac{\text{number of moles of }AgNO_3}{V_1}

V_1=\frac{0.0125955 moles}{0.225 M}=0.05598 L=55.98 mL

Volume of AgNO_3 required is 55.98 mL.

2)

Molarity=0.195 M=\frac{\text{number of moles}}{\text{volume of solution in liters}}

Number of moles of AgNO_3=0.195\times 0.023 L=0.004485 moles

According to reaction, 3 moles of AgNO_3 gives 1 mole of Ag_3PO_4, then 0.004485 moles of AgNO_3 will give:\frac{1}{3}\times 0.004485 moles of Ag_3PO_4 that is 0.001495 moles.

Mass of Ag_3PO_4 =

Moles of Ag_3PO_4 × Molar Mass of Ag_3PO_4

= 0.001495 moles × 418.58 g/mol = 0.62577 g

0.62577 grams of Ag_3PO_4 is produced.

7 0
3 years ago
Round the answer for the following question to the correct number of significant figures: 38,736 km ÷ 4784 km
uysha [10]

Answer:

Explanation:

38736 ÷ 4784 = 8.097

Sig Figs

4

8.097

Decimals

3

8.097

Scientific Notation

8.097 × 10^0

E-Notation

8.097e+0

Words

eight point zero nine seven

4 0
2 years ago
Explain how the random motion of molecules produces a concentration gradient and a net movement of solute
mixer [17]

Random motion of molecules produces a concentration gradient and a net movement of solute as  random movement of molecules causes diffusion that causes movement of molecules from high concentration to low concentration . No ATP is required in this process. This causes movement of solute molecules and causes concentration gradient.

3 0
3 years ago
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