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Fudgin [204]
3 years ago
7

For the reaction C + 2H2 → CH4, how many moles of hydrogen are needed to make 108.6 grams of methane, CH4 ?

Chemistry
1 answer:
dlinn [17]3 years ago
6 0

Answer:

RFM \: of \: methane \:  = 16 \: g \\ 16 \: g  \: are \: weighed \: by \: 1 \: mole \: of \: methane \\ 108.6 \: g \: are \: weighed \: by \: ( \frac{108.6}{16}  \times 1) \: moles \\  = 6.7875 \: moles \: of \: methane \\ from \: the \: equation :  \\ 1 \: mole \: of \: methane \: is \: formed \: by \: 2 \: moles \: of \: hydrogen \\ 6.7875 \: moles \: of \: methane \: will \: be \: produced \: by \: (6.7875 \times 2) \: moles \\  = 13.6 \: moles \: of \: hydrogen

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How long would it take a car traveling with a speed of 95 km/h to travel 250 km between Plainview and Cedar Crest?
antoniya [11.8K]
It's C. about 2.4 hours.
5 0
3 years ago
If a concentrated solution of acetic acid is 99.5 % HC2 H3 O2 and has a density of 1.05 g/mL, what is the concentration of this
cluponka [151]

Answer:

[CH₃COOH] = 17.4 M

Explanation:

Acetic acid → CH₃COOH

Molar mass → 60 g/mol

99.5% is percent by mass concentration. It means that 99.5 grams of solute are contained in 100g of solution.

Density → 1.05 g/mL. This data is always referred to solution, not solute!.

We determine solution's volume:

1.05 g/mL = 100 g / V → V = 100 g /1.05 g/mL → 95.2 mL

Now we know, that 99.5 g of acetic acid are contained in 95.2 mL

Let's convert to mmoles → 99.5 g / 60 g/mol = 1.66 moles

We convert solution's volume to L → 95.2 mL . 1L / 1000 mL = 0.0952 L

M (mol/L) = 1.66 mol / 0.0952 L = 17.4 M

5 0
3 years ago
The diatomic molecule of chlorine, cl2, is held together by a(n)____ covalent bond.
kvasek [131]

Answer : The diatomic molecule of chlorine, Cl₂, is held together by a SINGLE covalent bond.

Covalent Bond :

It is type of chemical bond, which is formed by sharing of electron between atoms . The covalent bond is formed between two non metals . The valance electron are shared to form the bond . The shared electrons are known as BONDING electron pair and the electron pair which do not take part in bonding are known as NON- BONDING electron pair. Example : O₂ , H₂ , H₂O, NH₃ etc .

Formation of covalent bond in Cl₂ :

Chlorine is present in group 17 in p block , It is a non metal .

The electronic configuration of Cl is : 1s² 2s² 2p⁶ 3s² 3p⁵ .

Since the outer shell is n= 3 , which has 7 electrons in it , hence Cl has 7 valence electrons in it .

From electronic configuration , it can be seen that Cl need 1 electron to complete its octet (3s² 3p⁶ ). Hence when two Cl atoms come close they share one-one electron with each other (as shown in image ) .

Now the octet of both the atom are complete and they are in stable state together .

When both Cl atom share one e⁻ , there is a bond formed between Cl atoms . One bond consists of 2⁻ . Hence in Cl₂ SINGLE covalent bond present .

Cl + Cl -> Cl₂

7 0
4 years ago
what evidence is there in the diagrams to support the classification of these substances as elements​
Novosadov [1.4K]

Awnser your loooking fo its got to be aluminium

Explanation:i took the dang subgect

5 0
3 years ago
A 10.0 cm3 sample of copper has a mass of 89.6 g. What is the density of copper
natali 33 [55]

Answer:

<h2>Density = 8.96 g/cm³</h2>

Explanation:

The density of a substance can be found by using the formula

Density =  \frac{mass}{volume}

From the question

mass of copper = 89.6 g

volume = 10 cm³

Substitute the values into the above formula and solve

That's

Density =  \frac{89.6}{10}

We have the final answer as

<h3>Density = 8.96 g/cm³</h3>

Hope this helps you

7 0
4 years ago
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