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Marta_Voda [28]
3 years ago
6

7over 8 times 4over 9 without multiplying

Mathematics
1 answer:
posledela3 years ago
4 0
11 over 13 I think is the answer
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Which of the following statements is true about the three quadrilaterals?
emmasim [6.3K]
A. D and E are similar but not congruent.
8 0
3 years ago
Find all points on the curve x=4cos(t),y=4sin(t) that have the slope of 12.
Marianna [84]

Answer:

\left (-\dfrac{4}{\sqrt{5}},\dfrac{8}{\sqrt{5}}\right )\text{ and }\left (\dfrac{4}{\sqrt{5}},-\dfrac{8}{\sqrt{5}}\right ).

Step-by-step explanation:

We need to find all the points on the curve x=4cos(t),y=4sin(t) that have the slope of 1/2.

x=4cos (t)

\dfrac{dx}{dt}=-4sin (t)

y=4sin (t)

\dfrac{dy}{dt}=4cos (t)

Now,

\dfrac{dy}{dx}=\dfrac{dy}{dt}\times \dfrac{dt}{dx}

\dfrac{dy}{dx}=4cos (t)\times \dfrac{1}{-4sin (t)}

\dfrac{dy}{dx}=-\cot t

So, slope of the curve is -\cot t.

-\cot t=\dfrac{1}{2}

-\tan t=2

\tan t=-2            ...(1)

Using \sec^2t=1+\tan^2t, we get

\sec^2t=1+(-2)^2

\sec^2t=1+4

\sec t=\pm \sqrt{5}

\cos t=\pm \dfrac{1}{\sqrt{5}}

Now,

\sin^2t=1-cos^2t

\sin t=\pm \sqrt{1-\dfrac{1}{5}}

\sin t=\pm \sqrt{\dfrac{4}{5}}

\sin t=\pm \dfrac{2}{\sqrt{5}}

It equation (1), tan(t) is negative. So, sin and cos have different signs.

If \sin t= \dfrac{2}{\sqrt{5}}, then \cos t=- \dfrac{1}{\sqrt{5}}.

x=4cos (t)=-\dfrac{4}{\sqrt{5}}

y=4sin (t)=\dfrac{8}{\sqrt{5}}

If \sin t=- \dfrac{2}{\sqrt{5}}, then \cos t= \dfrac{1}{\sqrt{5}}.

x=4cos (t)=\dfrac{4}{\sqrt{5}}

y=4sin (t)=-\dfrac{8}{\sqrt{5}}

Therefore, the two points are \left (-\dfrac{4}{\sqrt{5}},\dfrac{8}{\sqrt{5}}\right )\text{ and }\left (\dfrac{4}{\sqrt{5}},-\dfrac{8}{\sqrt{5}}\right ).

5 0
3 years ago
Urgen helpppppp please
GrogVix [38]
I think the correct answer iS D 
3 0
3 years ago
The expression 3 + 2(x - 5)2
Vlad [161]

9514 1404 393

Answer:

  D.  53 feet

Step-by-step explanation:

The value of the expression when x=0 is ...

  3 + 2(-5)² = 3 + 2(25) = 3 +50 = 53

The initial height of the ball is 53 feet.

6 0
3 years ago
What percent is represented by the shaded area?​
zhenek [66]

Answer:

90%, or 180%, it depends on if one rectangle equals one whole, if yes, then 180%, but if both rectangles equal one whole then 90%

8 0
3 years ago
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