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murzikaleks [220]
3 years ago
8

2NO(g) + O2 (g) --> 2NO2

Chemistry
1 answer:
Tatiana [17]3 years ago
5 0
Take 5 * 2/1 = 10 mol NO needed
10 mol * 30 g/mol = 300g

Answer C
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What volume is occupied by 0.109 molmol of helium gas at a pressure of 0.98 atmatm and a temperature of 307 K
KATRIN_1 [288]

Answer:

2.8 L

Explanation:

From the question given above, the following data were obtained:

Number of mole (n) = 0.109 mole

Pressure (P) = 0.98 atm

Temperature (T) = 307 K

Gas constant (R) = 0.0821 atm.L/Kmol

Volume (V) =?

The volume of the helium gas can be obtained by using the ideal gas equation as follow:

PV = nRT

0.98 × V = 0.109 × 0.0821 × 307

0.98 × V = 2.7473123

Divide both side by 0.98

V = 2.7473123 / 0.98

V = 2.8 L

Thus, the volume of the helium gas is 2.8 L.

6 0
2 years ago
What is the composition of the nuclei modeled by these symbols? How many protons and neutrons?
gayaneshka [121]

There are six protons and eight neutrons present in the carbon atom as shown.

<h3>What is the nucleus?</h3>

The nucleus of an atom consists of its protons and its neutrons. The protons are positively charged while the neutrons have no charge.

From the symbol of the element as shown in the question, we can see that there are six protons and eight neutrons present.

Learn more about nucleus of atoms:brainly.com/question/10658589

#SPJ1

6 0
1 year ago
At 1 atm of pressure and a temperature of 0 degrees celsius, which phases of H2O can exist?
NemiM [27]
B, because water is changing its state from solid to liquid (it's fusion in portuguese, don't know in english), so while it's changing, water has 2 states at the same time.
3 0
3 years ago
What happens when mix coke and milk
qwelly [4]

ωєℓℓ тнє ρнσѕρнσяι¢ α¢ι∂ мσℓє¢υℓєѕ αттα¢н тσ тнє мσℓє¢υℓєѕ σf тнє мιℓк, αи∂ тнαт ιи¢яєαѕєѕ тнє ∂єиѕιту αи∂ тнєи ѕєρєяαтєѕ тнєм fяσм тнє яєѕт σf тнє ℓιqυι∂ ιи ιт. тнє яємαιи∂єя σf тнє ℓιqυι∂ѕ,иσω нανιиg ℓєѕѕ ∂єиѕιту тнαи тнє ρнσѕρнσяι¢ α¢ι∂ѕ & тнє мιℓк мσℓє¢υℓєѕ, ѕσ ιт ιт иσω fℓσαтѕ σи тσρ.

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7 0
3 years ago
Read 2 more answers
A vessel of volume 100ml contains 10% of oxygen and 90% of an unknown gas. The gases diffuses in 86 second through a small hole
swat32

The molecular weight of unknown gas : 23.46 g/mol

<h3>Further explanation</h3>

Given

A vessel contains 10% of oxygen and 90% of an unknown gas.

diffuses rate of mixed gas = 86 s

diffuses rate of O₂ = 75 s

Required

the molecular weight of unknown gas (M)

Solution

The molecular weight of mixed gas :(M O₂=32 g/mol)

\tt 0.1\times 32+0.9\times M=3.2+0.9M

Graham's Law :

\tt \dfrac{r_{O_2}}{r_{mixed~gas}}=\sqrt{\dfrac{M_{mixed}}{M_{O_2}} }\\\\\dfrac{75}{86}=\sqrt{\dfrac{3.2+0.9M}{32} }\\\\0.76=\dfrac{3.2+0.9M}{32}\\\\24.32=3.2+0.9M\\\\21.12=0.9M\rightarrow M=23.46~g/mol

7 0
3 years ago
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