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Alex_Xolod [135]
2 years ago
7

A solution that contains 55.0 g of ascorbic acid (Vitamin C) in 250. g of water freezes at –2.34°C. Calculate the molar mass (in

units of g/mol) of the solute. K f of water is 1.86°C/m
Chemistry
1 answer:
Vaselesa [24]2 years ago
3 0

Answer:

M=174.87g/mol

Explanation:

Hello,

In this case, we consider the depression in the freezing point as:

\Delta T=-i*m*Kf

Whereas the van't hoff factor for ascorbic acid is 1 since it is covalent, thus, we solve for the molality as shown below:

(-2.34-0)\°C=-m*1.86\°C/m\\\\m=\frac{-2.34\°C}{-1.86\°C/m} =1.26m

Next, since molal units are mol/kg, we can compute the present moles of ascorbic acid in the 250 g (0.25kg) of water:

n=1.26mol/kg*0.25kg=0.315mol

Finally, the molar mass with the given 55.0 g of ascorbic acid:

M=\frac{55.0g}{0.315mol}\\ \\M=174.87g/mol

Regards.

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Answer:

Mass of Fe produced = 3.86785211069  ≈ 3.87 kg

Explanation:

From the question the chemical reaction can be written as follow :

Fe2O3 + C → Fe + CO  

Balance the equation

Fe2O3 + 3C → 2Fe + 3CO  

compute the molecular mass of Fe2O3 and atomic mass of Iron(Fe)

Molecular mass of Fe2O3 = 55.845(2) + 15.999(3) = 111.69 + 47.997 = 159.687 g

Atomic mass of iron = 55.845 g

From the balanced equation

159.687 g of Fe2O3  produces 2 ×  55.845 = 111.69 g of Fe(iron)

Convert the 5.53 kg to gram

1 kg = 1000 g

5.53 kg  = 5.53 × 1000 = 5530 g

since,

159.687 g of Fe2O3  produces 2 ×  55.845 = 111.69 g of Iron(Fe)

5530 g of  Fe2O3  will produce  

cross multiply

Mass of Fe produced =5530 × 111.69/159.687

Mass of Fe produced = 617645.7

/159.687

Mass of Fe produced = 3867.85211069  g

convert to kg

1000 g = 1 kg

3867.85211069   = 3867.85211069/1000

Mass of Fe produced = 3.86785211069  ≈ 3.87 kg

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