Electrons and protons because they are essentially always the same
Answer: What conclusion can be drawn from the statement that an element has high ionization energy and small atomic size? The element is most likely from Group 1A or 2A and in period 1 or 2. Describe how the atomic radius of an element is related to metallic character.
Explanation:
Answer:
The answer to your question is 40 L of NH₃
Explanation:
Data
Volume of NH₃ = x
mass of N₂ = 25 g
mass of H₂ = excess
Balanced chemical reaction
N₂ + 3H₂ ⇒ 2NH₃
Process
1.- Find the molar mass of N₂ and NH₃
N₂ = 14 x 2 = 28g
2NH₃ = 2[ 14 + 3] = 34 g
2.- Write a proportion to solve this problem
28 g of N₂ --------------- 34 g of NH₃
25 g of N₂ ------------- x
x = (25 x 34)/28
x = 30.36 g of NH₃
3.- Calculate the volume of NH₃
17 g of NH₃ -------------- 22.4 L
30.36 g of NH₃ -------- x
x = (30.36 x 22.4) / 17
x = 40 L
Answer:
1,869.97 grams of Be(NO3)2
Explanation:
Be(NO3)2 = Be N2 O6
Be=9.012182g/mole
N2=28.0134g/mole
O6=96g/mole
therefore Be(NO3)2 gives you 187.56g in one mole
so 9.97 moles means there is 9.97 times more
9.97mole Be(NO3)2 * 187.56g Be(NO3)2/1mole Be(NO3)2 = 1,869.97g of Be(NO3)2
