The process of adding hydrogen to the double bonds in unsaturated fatty acids to extend the shelf-life of food products is calle
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Answer:
The unit cell edge length for the alloy is 0.405 nm
Explanation:
Given;
concentration of Ag, = 78 wt%
concentration of Pd, = 22 wt%
density of Ag = 10.49 g/cm³
density of Pd = 12.02 g/cm³
atomic weight of Ag, = 107.87 g/mol
atomic weight of iron, = 106.4 g/mol
Step 1: determine the average density of the alloy
Step 2: determine the average atomic weight of the alloy
Step 3: determine unit cell volume
for a FCC crystal structure, there are 4 atoms per unit cell; n = 4
Step 4: determine the unit cell edge length
Vc = a³
= 0.405 nm
Therefore, the unit cell edge length for the alloy is 0.405 nm
Answer : The volume of 4.9 M stock solution used to prepare the solution is, 12.24 ml
Solution : Given,
Molarity of aqueous solution = 1.20 M = 1.20 mole/L
Volume of aqueous solution = 50.0 ml = 0.05 L
(1 L = 1000 ml)
Molarity of stock solution = 4.9 M = 4.9 mole/L
Formula used :
where,
= Molarity of aqueous
solution
= Molarity of
stock solution
= Volume of aqueous
solution
= Volume of
stock solution
Now put all the given values in this formula, we get the volume of stock solution.
By rearranging the term, we get
Therefore, the volume of 4.9 M stock solution used to prepare the solution is, 12.24 ml