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Anton [14]
3 years ago
8

Cuales son los tipos de galeria virtual

Computers and Technology
1 answer:
Lelu [443]3 years ago
5 0
¿Está usted preguntando cómo la galería virtual es importante, o el impacto que tiene.
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Manuel is working on a project in Visual Studio. He wants to keep this program showing on the entire desktop, but he also needs
patriot [66]

Answer:

d. Task View

Explanation:

Based on the scenario being described within the question it can be said that the best feature for this would be the Windows 10 task view. This is a task switcher and  virtual desktop system included in the Windows 10 operating system, and allow the individual user to quickly locate, manage, open or hide different windows/tasks. Such as having several projects open in different monitors running at the same time.

3 0
3 years ago
Which statement is false? Select one: a. Function printf does not care how large the array it is printing is. b. Function scanf
dusya [7]

Answer:

Option A

Explanation:

Because each function has specific amount of space allocated by default on the stack, so it cares about the length of the array being printed by it. By default the space is up to 100 kb but this size can be increased by setting it manually.

Option B is correct answer because scanf takes input from user until first space is hit.

6 0
3 years ago
An element in a web page that connects to a different location in the same page or a different page is a _____.
Softa [21]
I believe it would be the anchor element.

<a href="#"></a>

Correct me if I'm wrong.
3 0
3 years ago
Given an array as follows
slava [35]

Answer:

1) Method calcTotal:

  1. public static long calcTotal(long [][] arr2D){
  2.        long total = 0;
  3.        
  4.        for(int i = 0; i < arr2D.length; i++ )
  5.        {
  6.            for(int j = 0; j < arr2D[i].length; j++)
  7.            {
  8.                total = total + arr2D[i][j];
  9.            }
  10.        }
  11.        
  12.        return total;
  13.    }

Explanation:

Line 1: Define a public method <em>calcTotal</em> and this method accept a two-dimensional array

Line 2: Declare a variable, total, and initialize it with zero.

Line 4: An outer for-loop to iterate through every rows of the two-dimensional array

Line 6: An inner  for-loop to iterate though every columns within a particular row.

Line 8: Within the inner for-loop, use current row and column index, i and j, to repeatedly extract the value of each element in the array and add it to the variable total.

Line 12: Return the final total of all the element values as an output

Answer:

2) Method calcAverage:

  1. public static double calcAverage(long [][] arr2D){
  2.        double total = 0;
  3.        int count = 0;
  4.        
  5.        for(int i = 0; i < arr2D.length; i++ )
  6.        {
  7.            for(int j = 0; j < arr2D[i].length; j++)
  8.            {
  9.                total = total + arr2D[i][j];
  10.                count++;
  11.            }
  12.            
  13.        }
  14.        
  15.        double average = total / count;
  16.        
  17.        return average;
  18.    }

Explanation:

The code in method <em>calcAverage</em> is quite similar to method <em>calcTotal</em>. We just need to add a counter and use that counter as a divisor of total values to obtain an average.

Line 4: Declare a variable, count, as an counter and initialize it to zero.

Line 11: Whenever an element of the 2D array is added to the total, the count is incremented by one. By doing so, we can get the total number of elements that exist in the array.

Line 16: Use the count as a divisor to the total to get average

Line 18: Return the average of all the values in the array as an output.

Answer:

3) calcRowAverage:

  1. public static double calcRowAverage(long [][] arr2D, int row){
  2.        double total = 0;
  3.        int count = 0;
  4.        
  5.        for(int i = 0; i < arr2D.length; i++ )
  6.        {
  7.            if(i == row)
  8.            {
  9.                for(int j = 0; j < arr2D[i].length; j++)
  10.                {
  11.                    total = total + arr2D[i][j];
  12.                    count++;
  13.                }
  14.            }
  15.            
  16.        }
  17.        
  18.        double average = total / count;
  19.        
  20.        return average;
  21.    }

Explanation:

By using method <em>calcAverage </em>as a foundation, add one more parameter, row, in the method <em>calcRowAverage</em>. The row number is used as an conditional checking criteria to ensure only that particular row of elements will be summed up and divided by the counter to get an average of that row.

Line 1: Add one more parameter, row,

Line 8-15: Check if current row index, i, is equal to the target row number, proceed to sum up the array element in that particular row and increment the counter.

5 0
3 years ago
(Java) Write a program that accepts a number of minutes and converts it both to hours and days. For example, 6000 minutes is 100
iogann1982 [59]
Import java.util.Scanner;
public class MinutesConversion {
private static Scanner inputDevice;
public static void main(String[] args) {
int minutes, hours;
float days; // float for decimal point

inputDevice = new Scanner(System.in);
System.out.println("Please enter minutes for conversion >> ");
minutes = inputDevice.nextInt();
hours = minutes / 60;
days = hours / 24.0f;


System.out.println(+ minutes + " minutes is " + hours + " hour(s) or" + days " days");
}
}
6 0
3 years ago
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