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jok3333 [9.3K]
3 years ago
15

Recatangle ABCD is graphed in the coordinate plane. The following are the vertices of the rectangle: A(-2,1), B(3,1),C(3,4), and

D(-2,4).What is the area of the rectangle ABCD?
Mathematics
2 answers:
Cloud [144]3 years ago
7 0

Answer: 15

Step-by-step explanation:

When you plot the points, it makes a rectangle. The length is 5 units and the height is 3 units. 5 times 3 is 15

horsena [70]3 years ago
7 0

Answer: 16 units

Step-by-step explanation:

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4 years ago
1.)
VashaNatasha [74]

Answer:

1. z = -15

2. p = 7

3. h = -11

4. t = 14

5. q = 12

Step-by-step explanation:

1.

\frac{z}{-5}+1=4

Add -1 both sides,

\frac{z}{-5}+1-1=4-1\\\frac{z}{-5}=3

Multiply both sides by -5,

\frac{z}{-5}\times-5=3\times-5\\z=-15

2.

Distribute 3 in p+2 and then add -6p and -6 both sides.

3(p+2)=6p-15\\3\times p+3\times2 = 6p-15\\3p+6=6p-15\\3p-6p=-15-6\\-3p=-21\\p=\frac{-21}{-3}=7

3.

\frac{h-7}{2}=3(h+8)

Multiply both sides by 2,

\frac{h-7}{2}\times2=3(h+8)\times2\\h-7=6(h+8)\\h-7=6h+48

Add -6h and 7 both sides,

h-6h-7+7=6h-6h+48+7\\-5h=55\\h=\frac{55}{-5}\\h=-11

4.

4t+2-5=3(t+7)-9\\4t-3=3t+21-9\\4t-3=3t+12

Add -3t and 3 both sides.

4t-3t-3+3=3t-3t+12+3\\t=15

5.

2(q-4)=4(q-8)\\2q-8=4q-32

Add -2q and 8 both sides.

2q-8-4q+8=4q-4q-32+8\\-2q=-24\\q=\frac{-24}{-2}\\q=12

Therefore,

1. z = -15

2. p = 7

3. h = -11

4. t = 14

5. q = 12

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