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3 years ago

Graph the two lines 2x + 3y = 18 , 3x -4y > 16.

1 answer:

7 0

The domain and range for each line is all real numbers. This is because all numbers are possible to input into x and all y values exist.

The slope of the first line is -2/3 and the y intercept is 6. You can reach this conclusion by solving for y (putting it in slope intercept form).

The slope of the second one is 3/4. and the y intercept is all real numbers greater than -4. This is true because it is an inequality and you can find these numbers by solving for y.

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Please help meee I need this by today please help me hellpppp

Igoryamba

4.
A. 3x + 1.50y the variables are x and y
B. If x = 73 wristbands and 47 buttons then:
3(47) + 1.50(47)
141 + 70.5 = 211.5
There you go!!

4 0

2 years ago

Read 2 more answers

PLEASE HELP! WIL GIVE BRAINLLIEST!

yarga [219]

Answer:

First Graph is Correct

Step-by-step explanation:

We are given the inequality:

$n \leq 46$

This means any number EQUAL TO or LESS than 46

Since, we have "equal to", there should be a "closed" circle on 46 (it means 46 is included).

LESS THAN means all numbers to the "LEFT".

Looking at the 4 number lines, we can eliminate last 2 choices since they don't have closed circles.

As for the first two choices, the first choice is correct because it shows us all the numbers left of 46 and 46 included (signified by the closed circle).

So, the first number line is the solution

4 0

3 years ago

Can someone help me please.

Katyanochek1 [597]

The first fraction is 7/10.
The second bag has the same probability as the top so just copy the fractions into the boxes.
To calculate the probability of the same colour being chosen you follow these steps.
P(RR) = 3/10 x 4/9 = 12/90
P(GG) = 7/10 x 5/9 = 35/90
Then add the two fractions.
12/90 + 35/90 = 47/90
The last box is 47/90.

5 0

3 years ago

Michael is putting a circular window in a wall in his house. He measures out the radius of the window to be 3 feet, and decides

enyata [817]

Answer:

circumfrence = 2 x pi x r

C = 2 x 3.14 x 3

C = 18.84 feet

Don't agree with Conclusion.

Mistake was he didn't multiply by pi (3.14)

Step-by-step explanation:

3 0

3 years ago

Given a joint PDF, f subscript X Y end subscript (x comma y )equals c x y comma space 0 less than y less than x less than 4, (1)

ioda

(1) Looks like the joint density is

$f_{X,Y}(x,y)=\begin{cases}cxy&\text{for }0$

In order for this to be a proper density function, integrating it over its support should evaluate to 1. The support is a triangle with vertices at (0, 0), (4, 0), and (4, 4) (see attached shaded region), so the integral is

$\displaystyle\int_0^4\int_y^4 cxy\,\mathrm dx\,\mathrm dy=\int_0^4\frac{cy}2(4^2-y^2)=32c=1$

$\implies\boxed{c=\dfrac1{32}}$

(2) The region in which X > 2 and Y < 1 corresponds to a 2x1 rectangle (see second attached shaded region), so the desired probability is

$P(X>2,Y$

(3) Are you supposed to find the marginal density of X, or the conditional density of X given Y?

In the first case, you simply integrate the joint density with respect to y:

$f_X(x)=\displaystyle\int_{-\infty}^\infty f_{X,Y}(x,y)\,\mathrm dy=\int_0^x\frac{xy}{32}\,\mathrm dy=\begin{cases}\frac{x^3}{64}&\text{for }0$

In the second case, we instead first find the marginal density of Y:

$f_Y(y)=\displaystyle\int_y^4\frac{xy}{32}\,\mathrm dx=\begin{cases}\frac{16y-y^3}{64}&\text{for }0$

Then use the marginal density to compute the conditional density of X given Y:

$f_{X\mid Y}(x\mid y)=\dfrac{f_{X,Y}(x,y)}{f_Y(y)}=\begin{cases}\frac{2xy}{16y-y^3}&\text{for }y$

6 0

3 years ago