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yulyashka [42]
3 years ago
11

Suppose you want to represent a triangle with sides 12 feet, 16 feet, and 18 feet on a drawing where 1 inch = 2 feet. How long s

hould the sides of the triangle be in inches? The sides of the triangle on the drawing should be _____. 14, 18 and 20 10, 14 and 16 6, 8 and 9 24, 32 and 36
Mathematics
1 answer:
slega [8]3 years ago
8 0

Answer:

<u>The correct answer is C. 6, 8 and 9 inches.</u>

Step-by-step explanation:

1. Let's review all the information provided for answering the questions properly:

Length of the sides of the triangle = 12 feet, 16 feet and 18 feet.

Scale used : 1 inch = 2 feet.

2. How long should the sides of the triangle be in inches?

For calculating the length of the sides of the triangle in the draw, we use the scale this way:

1st Side = 12 feet

12 feet/2 = 6 inches

2nd Side = 16 feet

16 feet/2 = 8 inches

3rd Side = 18 feet

18 feet/2 = 9 inches

<u>The correct answer is C. 6, 8 and 9 </u>

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What is the equation of the line that is parallel to the given
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Y=- 6

Because the slope is 0, the equation would be y=0x+b

-6=0+b

b=-6
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3 years ago
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What are the solutions to this quadratic equation? x2+6x-5 A. B. C. D.
faltersainse [42]
Factoring x2-6x+5

The first term is, x2 its coefficient is 1 .
The middle term is, -6x its coefficient is -6 .
The last term, "the constant", is +5

Step-1 : Multiply the coefficient of the first term by the constant 1 • 5 = 5

Step-2 : Find two factors of 5 whose sum equals the coefficient of the middle term, which is -6 .

-5 + -1 = -6 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -5 and -1
x2 - 5x - 1x - 5

Step-4 : Add up the first 2 terms, pulling out like factors :
x • (x-5)
Add up the last 2 terms, pulling out common factors :
1 • (x-5)
Step-5 : Add up the four terms of step 4 :
(x-1) • (x-5)
Which is the desired factorization

Equation at the end of step
1
:

(x - 1) • (x - 5) = 0
STEP
2
:
Theory - Roots of a product

2.1 A product of several terms equals zero.

When a product of two or more terms equals zero, then at least one of the terms must be zero.

We shall now solve each term = 0 separately

In other words, we are going to solve as many equations as there are terms in the product

Any solution of term = 0 solves product = 0 as well.

Solving a Single Variable Equation:

2.2 Solve : x-1 = 0

Add 1 to both sides of the equation :
x = 1

Solving a Single Variable Equation:

2.3 Solve : x-5 = 0

Add 5 to both sides of the equation :
x = 5

Supplement : Solving Quadratic Equation Directly

Solving x2-6x+5 = 0 directly
Earlier we factored this polynomial by splitting the middle term. let us now solve the equation by Completing The Square and by using the Quadratic Formula

Parabola, Finding the Vertex:

3.1 Find the Vertex of y = x2-6x+5

Parabolas have a highest or a lowest point called the Vertex . Our parabola opens up and accordingly has a lowest point (AKA absolute minimum) . We know this even before plotting "y" because the coefficient of the first term, 1 , is positive (greater than zero).

Each parabola has a vertical line of symmetry that passes through its vertex. Because of this symmetry, the line of symmetry would, for example, pass through the midpoint of the two x -intercepts (roots or solutions) of the parabola. That is, if the parabola has indeed two real solutions.

Parabolas can model many real life situations, such as the height above ground, of an object thrown upward, after some period of time. The vertex of the parabola can provide us with information, such as the maximum height that object, thrown upwards, can reach. For this reason we want to be able to find the coordinates of the vertex.

For any parabola,Ax2+Bx+C,the x -coordinate of the vertex is given by -B/(2A) . In our case the x coordinate is 3.0000

Plugging into the parabola formula 3.0000 for x we can calculate the y -coordinate :
y = 1.0 * 3.00 * 3.00 - 6.0 * 3.00 + 5.0
or y = -4.000

Parabola, Graphing Vertex and X-Intercepts :

Root plot for : y = x2-6x+5
Axis of Symmetry (dashed) {x}={ 3.00}
Vertex at {x,y} = { 3.00,-4.00}
x -Intercepts (Roots) :
Root 1 at {x,y} = { 1.00, 0.00}
Root 2 at {x,y} = { 5.00, 0.00}
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A ball is launched out of a cannon that is 24 feet off the ground. The height of the ball after "t" seconds is represented by
Olegator [25]

Given:

The height of ball is represented by the below function:

h(t)=-16t^2+20t+24

To find:

The number of seconds it will take to reach the ground.

Solution:

We have,

h(t)=-16t^2+20t+24

At ground level, the height of ball is 0, i.e., h(t)=0.

-16t^2+20t+24=0

Taking out greatest common factor.

-4(4t^2-5t-6)=0

4t^2-5t-6=0

Splitting the middle term, we get

4t^2-8t+3t-6=0

4t(t-2)+3(t-2)=0

(t-2)(4t+3)=0

Using zero product property, we get

(t-2)=0 and (4t+3)=0

t=2 and t=-\dfrac{3}{4}

Time cannot be negative, so t=2.

Therefore, the ball will reach the ground after 2 seconds.

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3 years ago
Suppose GRE Verbal scores are normally distributed with a mean of 461 and a standard deviation of 118. A university plans to rec
nirvana33 [79]

Answer:

The minimum score required for recruitment is 668.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 461 \sigma = 118

Top 4%

A university plans to recruit students whose scores are in the top 4%. What is the minimum score required for recruitment?

Value of X when Z has a pvalue of 1-0.04 = 0.96. So it is X when Z = 1.75.

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1.75 = \frac{X - 461}{118}

X - 461 = 1.75*118

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Rounded to the nearest whole number, 668

The minimum score required for recruitment is 668.

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