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Mrrafil [7]
3 years ago
13

What is the exact value of arccos(−2√2) ?

Mathematics
1 answer:
Strike441 [17]3 years ago
4 0

Answer:

See explanation

Step-by-step explanation:

The range of the cosine function is -1\le \cos x\le 1

Therefore arc \cos (-2\sqrt{2}) is not defined.

Assuming your question is rather arc \cos (-\frac{\sqrt{2}}{2})

Then arc \cos (-\frac{\sqrt{2}}{2})=\pi-arc \cos (\frac{\sqrt{2}}{2})  in the second quadrant.

arc \cos (-\frac{\sqrt{2}}{2})=\pi-\frac{\pi}{4}

arc \cos (-\frac{\sqrt{2}}{2})=\frac{3\pi}{4}

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A grocery store sells a bag of 6 oranges for $3.84. What is the cost of oranges, in
Vilka [71]

Answer:

Each orange would cost $0.64.

Step-by-step explanation:

If you do 3.84 and divide that by 6, you would get the answer of $0.64 for each orange.

3 0
3 years ago
Use the distance formula to determine whether ABCD below is a parallelogram. A(-3,2) B(-3,3) C (5,-3) D (-1.-5)
Pani-rosa [81]

Answer:

ABCD is not a parallelogram

Step-by-step explanation:

Use the distance formula to determine whether ABCD below is a parallelogram. A(-3,2) B(-3,3) C (5,-3) D (-1.-5)

We have to find the length of the sides of the parallelogram using the formula below

= √(x2 - x1)² + (y2 - y1)² when given vertices (x1, y1) and (x2, y2)

For side AB

A(-3,2) B(-3,3)

= √(-3 -(-3))² + (3 -2)²

= √0² + 1²

= √1

= 1 unit

For side BC

B(-3,3) C (5,-3)

= √(5 -(-3))² + (-3 -3)²

= √8² + -6²

= √64 + 36

= √100

= 10 units

For side CD

C (5,-3) D (-1.-5)

= √(-1 - 5)² + (-5 - (-3))²

= √-6² + -2²

= √36 + 4

= √40 units

For sides AD

A(-3,2) D (-1.-5)

= √(-1 - (-3))² + (-5 -2)²

= √(2² + -7²)

= √(4 + 49)

= √53 units

A parallelogram is a quadrilateral with it's opposite sides equal

From the above calculation

Side AB ≠ CD

BC ≠ AD

Therefore, ABCD is not a parallelogram

3 0
3 years ago
Can you help me in this question?
gregori [183]

Answer: I think its B

Step-by-step explanation: My friend answered it.

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3 years ago
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