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Mrrafil [7]
3 years ago
13

What is the exact value of arccos(−2√2) ?

Mathematics
1 answer:
Strike441 [17]3 years ago
4 0

Answer:

See explanation

Step-by-step explanation:

The range of the cosine function is -1\le \cos x\le 1

Therefore arc \cos (-2\sqrt{2}) is not defined.

Assuming your question is rather arc \cos (-\frac{\sqrt{2}}{2})

Then arc \cos (-\frac{\sqrt{2}}{2})=\pi-arc \cos (\frac{\sqrt{2}}{2})  in the second quadrant.

arc \cos (-\frac{\sqrt{2}}{2})=\pi-\frac{\pi}{4}

arc \cos (-\frac{\sqrt{2}}{2})=\frac{3\pi}{4}

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