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3 years ago

What is the exact value of arccos(−2√2) ?

Mathematics

1 answer:

Strike441 [17]3 years ago

4 0

Answer:

See explanation

Step-by-step explanation:

The range of the cosine function is $-1\le \cos x\le 1$

Therefore $arc \cos (-2\sqrt{2})$ is not defined.

Assuming your question is rather $arc \cos (-\frac{\sqrt{2}}{2})$

Then $arc \cos (-\frac{\sqrt{2}}{2})=\pi-arc \cos (\frac{\sqrt{2}}{2})$ in the second quadrant.

$arc \cos (-\frac{\sqrt{2}}{2})=\pi-\frac{\pi}{4}$

$arc \cos (-\frac{\sqrt{2}}{2})=\frac{3\pi}{4}$

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goldfiish [28.3K]

Function A isn't linear because it doesn't have a pattern on the y and Function B is a function because it has a pattern of .75 on the y or output

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4 years ago

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balu736 [363]

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3 years ago

Five years after 650 high school seniors graduated, 400 had a college degree and 310 were married. Half of the students with a c

DedPeter [7]

Answer:

The probability that a student has a college degree or is not married is 0.8308.

Step-by-step explanation:

The information provided is:

Total number of high school seniors (N) = 650.

Number of seniors with a college degree (n (C)) = 400.

Number of seniors who were married, (n (M)) = 310.

Consider the Venn diagram below.

The probability of an event, say E, is the ratio of the favorable outcomes of E to the total number of outcomes of the experiment.

That is,

$P(E)=\frac{n(E)}{N}$

Here,

n (E) = favorable outcomes of E

N = total number of outcomes of the experiment.

The probability of the union of two events is:

$P(A\cup B)=P(A)+P(B)-P(A\cap B)=\frac{n(A)+n(B)-n(A\cap B)}{N}$

Compute the probability that a student has a college degree or is not married as follows:

$P(C\cup M^{c})=\frac{n(C)+n(M^{c})-n(C\cap M^{c})}{N}$

From the Venn diagram:

n (C) = 400

n ( $M^{c}$ ) = N - n (M) = 650 - 310 = 340

n (C ∩ $M^{c}$ ) = 200

The value of P (C ∪ $M^{c}$ ) is:

$P(C\cup M^{c})=\frac{n(C)+n(M^{c})-n(C\cap M^{c})}{N}=\frac{400+340-200}{650}=0.83077\approx0.8308$

Thus, the probability that a student has a college degree or is not married is 0.8308.

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3 years ago

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Klaus Klawn has kept track of his algebra test scores and recorded them in the table below.

Anna11 [10]

Answer:

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Step-by-step explanation:

Domain of a function is always defined by the input values (x-values).

Similarly range of any function is defined by the output values (y-values).

From the table given in this question,

Units given in the table will define the domain of the data.

Therefore, domain will be the set of numbers {3, 1, 2, 4, 6, 5}.

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3 years ago

A box plot is shown. The left-most point on the plot is 20 and the right-most point is 95. The box is labeled 35 on the left edg

Dennis_Churaev [7]

"The box plot tells us about the lower limit, first quartile, median, third quartile, and upper limit.

Step-by-step explanation:

Box plot:

It displays the five-number summary of a set of data. The five-number summary is the lower limit, first quartile, median, third quartile, and upper limit. We draw a box in a box plot from the first quartile to the third quartile. A vertical line goes through the box which represents the median. Anything that lies beyond the upper limit or the lower limit is know as an outlier.

From the information given, we can say that:

The left-most point on the plot is 20 and the right-most point is 95 which means 20 and 95 are the lower and upper limit respectively. The box is labeled 35 on the left edge and 60 on the right edge which means 35 is the first quartile and 60 is the the third quartile. A vertical line is drawn inside the rectangle at the point 55 which means 55 is the median of given data. We cannot know about the mean of data with the given information."

(this is kind of an answer, I hope it's helpful)

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3 years ago

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