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Alex_Xolod [135]
2 years ago
14

use the point–slope formula to write an equation of the line that passes through(-5, -16 )and has a slope of m = 3 . Write the a

nswer in slope–intercept form (if possible).
Mathematics
1 answer:
scoray [572]2 years ago
5 0

Answer:

y + 16 = 3(x + 5)

Step-by-step explanation:

When you write an equation in point-slope form, you only need two things: a point and a slope.

Given:

  • point: (-5, -16)
  • slope (m): 3

The standard point-slope equation is

y - y₁ = m(x - x₁)

Plug in what you know.

y - (-16) = 3(x - (-5))

Simplify.

y + 16 = 3(x + 5)

This is your equation.

Learn with another example:

brainly.com/question/24436844

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7.6x = 64
x = 64/7.6
x = <span> <span> <span> 8.4210526316 </span> </span> </span>
So, 3.05 is NOT the solution

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Read 2 more answers
In the diagram below, AC and CB, AB and CD, and m(angle)A=33 degrees. Find M(angle)B
hoa [83]

Answer:

15°.

Step-by-step explanation:

1. Angles ADC and CDB are supplementary, thus

m∠ADC+m∠CDB=180°.

Since m∠ADC=115°, you have that m∠CDB=180°-115°=65°.

2. Triangle BCD is isosceles triangle, because it has two congruent sides CB and CD. The base of this triangle is segment BD. Angles that are adjacent to the base of isosceles triangle are congruent, then

m∠CDB=m∠CBD=65°.

The sum of the measures of interior angles of triangle is 180°, therefore,

m∠CDB+m∠CBD+m∠BCD=180° and

m∠BCD=180°-65°-65°=50°.

3. Triangle ABC is isosceles, with base BC. Then

m∠ABC=m∠ACB.

From the previous you have that m∠ABC=65° (angle ABC is exactly angle CBD). So

m∠ACB=65°.

4. Angles BCD and DCA together form angle ACB. This gives you

m∠ACB=m∠ACD+m∠BCD,

m∠ACD=65°-50°=15°.

Have a good Day!

7 0
2 years ago
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