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Zolol [24]
3 years ago
12

Rough surfaces do not absorb radiation as well as smooth True False

Physics
1 answer:
AnnZ [28]3 years ago
5 0
In my opinion the answer is false
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A horse has a momentum of 25 kg*m/s and a velocity of 2.5 m/s. What is the horse mass?
Ne4ueva [31]
<h3>Answer:  10 kg</h3>

==================================================

Work Shown:

We have these variables

  • p = momentum = 25 kg*m/s
  • m = mass = unknown
  • v = velocity = 2.5 meters per second

Solving for the mass gets us...

p = m*v

25 = m*2.5

25/2.5 = m

10 = m

m = 10

The mass of the horse is 10 kg.

6 0
3 years ago
The speed of sound I gases depends on <br> a humidity <br> b air<br> c temperature <br> d visibility
Mazyrski [523]

The speed of sound in gases is represented mathematically as:

v(sound)  = √γRT/M

where γ = adiabatic constant which is the ratio of the heat capacities at constant pressure and constant volume; Cp/Cv

R = gas constant

T = temperature

M = molar mass of the gas

Hence, the speed of sound in gas is directly proportional to the square root of temperature.

Ans: c) temperature

4 0
3 years ago
An airplane is traveling at 250 m/s in level flight. If the airplane is to make a change in direction, it must travel is a horiz
Nonamiya [84]

Answer:

The radius of curvature of the curved path of the airplane is 23784.356 meters (23.784 kilometers).

Explanation:

We assume that airplane can be represented as a particle. The free body diagram of the vehicle is presented below as attachment, whose variables are:

W - Weight of the airplane, measured in newtons.

F - Lift, measured in newtons.

\theta - Banking angle, measured in sexagesimal degrees.

The equations of equilibrium associated with the airplane are, respectively:

\Sigma F_{r} = F\cdot \sin \theta = m\cdot \frac{v^{2}}{R} (Eq. 1)

\Sigma F_{z} = F\cdot \cos \theta - W = 0 (Eq. 2)

From (Eq. 2):

F = \frac{W}{\cos \theta}

In (Eq. 1):

W\cdot \tan \theta = m\cdot \frac{v^{2}}{R}

By using the definition of weight, we eliminate the mass of the airplane:

g\cdot \tan \theta = \frac{v^{2}}{R}

Where:

g - Gravitational acceleration, measured in meters per square second.

v - Speed, measured in meters per second.

R - Radius of curvature, measured in meters.

Lastly, we clear the radius of curvature with the expression:

R = \frac{v^{2}}{g\cdot \tan \theta}

If we know that v = 250\,\frac{m}{s}, g = 9.807\,\frac{m}{s^{2}} and \theta = 15^{\circ}, the radius of curvature is:

R = \frac{\left(250\,\frac{m}{s} \right)^{2}}{\left(9.807\,\frac{m}{s^{2}} \right)\cdot \tan 15^{\circ}}

R = 23784.356\,m

The radius of curvature of the curved path of the airplane is 23784.356 meters (23.784 kilometers).

6 0
4 years ago
The Earth's place in space can be described as _________.
Olin [163]
The answer is B because if you use process of elimination, you find that A is invalid because Venus is the second planet. C is out because Mars is the 4th planet. D is out because we are nowhere  near the Andromeda Galaxy. We are millions of light years away.
4 0
3 years ago
Read 2 more answers
If you drop a bowling ball, a tennis ball, and a feather from the top of a tall building at the same time which one will hit the
Whitepunk [10]
In the absence of air resistance the result is D .
6 0
3 years ago
Read 2 more answers
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