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2 years ago

A horse has a momentum of 25 kg*m/s and a velocity of 2.5 m/s. What is the horse mass?

Physics

1 answer:

Ne4ueva [31]2 years ago

6 0

<h3>Answer: 10 kg</h3>

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Work Shown:

We have these variables

p = momentum = 25 kg*m/s
m = mass = unknown
v = velocity = 2.5 meters per second

Solving for the mass gets us...

p = m*v

25 = m*2.5

25/2.5 = m

10 = m

m = 10

The mass of the horse is 10 kg.

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When are magnets attracted and when are they repelled.

vova2212 [387]

Magnets are attracted when each of the different sides, most commonly known as "North" and "South", are facing each other. They repel when North and North, or South and South are facing each other.

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3 years ago

You set your stationary bike on a high 80-N friction-like resistive force and cycle for 30 min at a speed of 8.0 m/s . Your body

stellarik [79]

A) The change in internal chemical energy is $1.15\cdot 10^7 J$

B) The time needed is 1 minute

Explanation:

First of all, we start by calculating the power output of you and the bike, given by:

$P=Fv$

where

F = 80 N is the force that must be applied in order to overcome friction and travel at constant speed

v = 8.0 m/s is the velocity

Substituting,

$P=(80)(8.0)=640 W$

The energy output is related to the power by the equation

$P=\frac{E}{t}$

where:

P = 640 W is the power output

E is the energy output

$t = 30 min \cdot 60 = 1800 s$ is the time elapsed

Solving for E,

$E=Pt=(640)(1800)=1.15\cdot 10^6 J$

Since the body is 10% efficient at converting chemical energy into mechanical work (which is the output energy), this means that the change in internal chemical energy is given by

$\Delta E = \frac{E}{0.10}=\frac{1.15\cdot 10^6}{0.10}=1.15\cdot 10^7 J$

From the previous part, we found that in a time of

t = 30 min

the amount of internal chemical energy converted is

$E=1.15\cdot 10^7 J$

Here we want to find the time t' needed to convert an amount of chemical energy of

$E'=3.8\cdot 10^5 J$

So we can setup the following proportion:

$\frac{t}{E}=\frac{t'}{E'}$

And solving for t',

$t'=\frac{E't}{E}=\frac{(3.8\cdot 10^5)(30)}{1.15\cdot 10^7}=1 min$

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3 years ago

1. Determine the image distance in each of the following.

miskamm [114]

It is given that for the convex lens,

Case 1.

u=−40cm

f=+15cm

Using lens formula

−

v=+24.3cm

The image in formed in this case at a distance of 24.3cm in left of lens.

Case 2.

A point source is placed in between the lens and the mirror at a distance of 40 cm from the lens i.e. the source is placed at the focus of mirror, then the rays after reflection becomes parallel for the lens such that

u=∞

f=15cm

Now, using mirror’s formula

∞

v=+15cm

The image is formed at a distance of 15cm in left of mirror

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3 years ago

The speed of a wave changes depending on the temperature of the medium. What do you think is the reason for this?

igor_vitrenko [27]

Answer: Because of the different wave speed from light and sound. Explanation: There is a major difference between the speed wave of light and sound, light travels at 186, 282 miles per second, and sound can travel at different speeds and its significantly slower so it is easier to measure it

Explanation:

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3 years ago

A coil of Nichrome wire is 25.0 m long. The wire has a diameter of 0.400mm and is at 20.0°C. If it carries a current of 0.500 A,

yaroslaw [1]

The power delivered to the coil is 0.5 Watts

<h3>Resistivity of a material</h3>

The formula for calculating the power delivered to it is expressed according to the equation

Power = I²R

where

I is the current

R is the resistance

Given

Current = 0.500A

Determine the resistance using the resistivity formula

R = ρL/A

Substitute the given parameters

R = 10^-6*(25)/0.002²

R = 2ohms

Substitute

Power = I²R

Power = (0.5)²(2)

Power = 0.5watts

Hence the power delivered to the coil is 0.5 Watts

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2 years ago